Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Experiment with Gallium: The goal of my experiment is to prove that the heat capacity of gallium is 0.37 J/gC by choosing masses and initial temperatures of both water and gallium. I'm solving for the final temperature using this equation: Mw Cw ΔT = Mg Cg ΔT, where M is mass, C is heat capacity, and ΔT is (final temperature - initial temperature). w refers to water and g refers to gallium. I chose a cold temperature for water and a warmer temperature for gallium, both below the melting point of gallium, but each time the temperature of the mixture is cooler than the water temperature.

Chemistry
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

Usually when a cold temperature is mixed with a warmer temperature, the resulting mixture has a temperature than is in the middle. Does this concept not apply to gallium?
It does, so it's odd that you'd measure that...
Go ahead and show your calculations. Your procedure seems okay, so the error may lie in how you're substituting in your values.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

what temperature is your gallium gonna be?
Mw = 14.333g Cw = 4.18 J/gC Initial Temp. of Water = 22 C Mg = 21.217 g Cg = 0.37 J/gC Initial Temp. of Gallium = 25 C Mw Cw ΔT = Mg Cg ΔT (14.333g)(4.18 J/gC)(Final Temp. - 22C) = (21.217g)(0.37 J/gC)(Final Temp. - 25C) (59.912 J/C)(Final Temp. - 22C) = (7.850 J/C)(Final Temp.-25 C) -- I distributed here -- (59.912 J/C * Final Temp.)(-1318.064 J) = (7.850 J/C * Final Temp.)(-196.25 J) (52.062 J/C * Final Temp.) = 1121.814 J Final Temp. = 21.547 C
Oh, I thought you meant that the problem was you MEASURED the temperature to be lower. The calculation is incorrect..... the two MC delta T's add to zero, so one equals the negative of the other.

Not the answer you are looking for?

Search for more explanations.

Ask your own question