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Experiment with Gallium:
The goal of my experiment is to prove that the heat capacity of gallium is 0.37 J/gC by choosing masses and initial temperatures of both water and gallium. I'm solving for the final temperature using this equation: Mw Cw ΔT = Mg Cg ΔT, where M is mass, C is heat capacity, and ΔT is (final temperature  initial temperature). w refers to water and g refers to gallium.
I chose a cold temperature for water and a warmer temperature for gallium, both below the melting point of gallium, but each time the temperature of the mixture is cooler than the water temperature.
 one year ago
 one year ago
Experiment with Gallium: The goal of my experiment is to prove that the heat capacity of gallium is 0.37 J/gC by choosing masses and initial temperatures of both water and gallium. I'm solving for the final temperature using this equation: Mw Cw ΔT = Mg Cg ΔT, where M is mass, C is heat capacity, and ΔT is (final temperature  initial temperature). w refers to water and g refers to gallium. I chose a cold temperature for water and a warmer temperature for gallium, both below the melting point of gallium, but each time the temperature of the mixture is cooler than the water temperature.
 one year ago
 one year ago

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CopythatBest ResponseYou've already chosen the best response.1
Usually when a cold temperature is mixed with a warmer temperature, the resulting mixture has a temperature than is in the middle. Does this concept not apply to gallium?
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.0
It does, so it's odd that you'd measure that...
 one year ago

XishemBest ResponseYou've already chosen the best response.0
Go ahead and show your calculations. Your procedure seems okay, so the error may lie in how you're substituting in your values.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
what temperature is your gallium gonna be?
 one year ago

CopythatBest ResponseYou've already chosen the best response.1
Mw = 14.333g Cw = 4.18 J/gC Initial Temp. of Water = 22 C Mg = 21.217 g Cg = 0.37 J/gC Initial Temp. of Gallium = 25 C Mw Cw ΔT = Mg Cg ΔT (14.333g)(4.18 J/gC)(Final Temp.  22C) = (21.217g)(0.37 J/gC)(Final Temp.  25C) (59.912 J/C)(Final Temp.  22C) = (7.850 J/C)(Final Temp.25 C)  I distributed here  (59.912 J/C * Final Temp.)(1318.064 J) = (7.850 J/C * Final Temp.)(196.25 J) (52.062 J/C * Final Temp.) = 1121.814 J Final Temp. = 21.547 C
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.0
Oh, I thought you meant that the problem was you MEASURED the temperature to be lower. The calculation is incorrect..... the two MC delta T's add to zero, so one equals the negative of the other.
 one year ago
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