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aceace
 3 years ago
Logarithm Question!!!
aceace
 3 years ago
Logarithm Question!!!

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aceace
 3 years ago
Best ResponseYou've already chosen the best response.0\[\log_{4}0.125 \] ... evaluate without a calculator

zordoloom
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, that's simple. Do you know how to do base change?

zordoloom
 3 years ago
Best ResponseYou've already chosen the best response.0You divide (log(0.125)/(log(4))

zordoloom
 3 years ago
Best ResponseYou've already chosen the best response.0There is really no other way to enter it in a calculator

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0So the log equals some unknown quantity, let's call it x. \[\large \log_{4} 0.125=x\] Do you know how to rewrite this as an exponential?

zordoloom
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, sorry, I didn't notice the no calculator allowed. Okay....

aceace
 3 years ago
Best ResponseYou've already chosen the best response.0i got it though.... i'll show you the method and tell me if its right

aceace
 3 years ago
Best ResponseYou've already chosen the best response.0\[\log_{4} 8\] then \[(\log_{4}2 + \log_{4}4)\] then (0.5 +1) then 1.5

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm yah I suppose that works! :) That's a little different than how I would have done it. But it get's you familiar with log rules, so that's good :D

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.10.125 = 1/8 and let \(x = \log_4\dfrac{1}{8}\) Convert it to exponent form, then find x

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Yah that was the other way c: hehe Either way though!
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