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dellzasaur
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Can someone please check my work?? Wanna make sure I'm doing this right! Simply each number by using the imaginary number i.
thanks!
 2 years ago
 2 years ago
dellzasaur Group Title
Can someone please check my work?? Wanna make sure I'm doing this right! Simply each number by using the imaginary number i. thanks!
 2 years ago
 2 years ago

This Question is Closed

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{7}\] = 7i or \[i \sqrt{7}\]
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{81}\] = 3i
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{16}\] = \[2i \sqrt{4}\]
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
\[3\sqrt{9}\] = \[3i\]
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
The last one is wrong.
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@dido525 Oh wow!! Thank you. I can't believe I'm doing these somewhat right lol. Would it be \[3i \sqrt{3}\] ?? And there was also a problem that was \[\sqrt{72}\] I got: \[2i \sqrt{3}\]
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
The last one should be 9i.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Well think about it WITHOUT the negative.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352593737003:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352593754329:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Now what would you do?
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
is that a 4 and 18? I would think to factor them to 2 x 2 and 9 x 2 maybe
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
but inside of the radicals
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
dw:1352593862710:dw
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@Dido525
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352594047004:dw
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@Dido525 Oh ok! That made since. I was using 8, 9, and i to make 72
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@Dido525 Thank you so much for all your help :) Makes me feel more confident about simplying them!
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
*simplifying whoops
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{72}=\sqrt{(1)\cdot2\cdot 36}\] \[=6i\sqrt{2}\]
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Okay that works too.
 2 years ago

chaguanas Group TitleBest ResponseYou've already chosen the best response.0
Getting the i right, but need to look at \[\sqrt{81} and \sqrt{16}\]
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@chaguanas Would I do \[3i \sqrt{3}\] for 81? and 4i or \[4i \sqrt{4}\] for 16?
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
do you know what \(\sqrt{81}\)is?
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@Zarkon 9
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
well...\[\sqrt{81}=\sqrt{(1)81}=i9=9i\]
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@Zarkon Ohh so that's how you do it. You wouldn't factor the 9 out to a 3?
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
for any \(a>0\) \[\sqrt{a^2}=a\cdot i\] so \[\sqrt{81}=\sqrt{9^2}=9i\]
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{16}=\sqrt{4^2}=4i\]
 2 years ago

dellzasaur Group TitleBest ResponseYou've already chosen the best response.1
@Zarkon Oh alright! I'm not sure if my teacher taught me about the a>0 thing but that makes sense. Thank you very much :) Explained a lot.
 2 years ago
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