A community for students.
Here's the question you clicked on:
 0 viewing
dellzasaur
 2 years ago
Can someone please check my work?? Wanna make sure I'm doing this right! Simply each number by using the imaginary number i.
thanks!
dellzasaur
 2 years ago
Can someone please check my work?? Wanna make sure I'm doing this right! Simply each number by using the imaginary number i. thanks!

This Question is Closed

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{7}\] = 7i or \[i \sqrt{7}\]

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{16}\] = \[2i \sqrt{4}\]

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1\[3\sqrt{9}\] = \[3i\]

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1@dido525 Oh wow!! Thank you. I can't believe I'm doing these somewhat right lol. Would it be \[3i \sqrt{3}\] ?? And there was also a problem that was \[\sqrt{72}\] I got: \[2i \sqrt{3}\]

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0The last one should be 9i.

Dido525
 2 years ago
Best ResponseYou've already chosen the best response.0Well think about it WITHOUT the negative.

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1is that a 4 and 18? I would think to factor them to 2 x 2 and 9 x 2 maybe

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1but inside of the radicals

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1352593862710:dw

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1@Dido525 Oh ok! That made since. I was using 8, 9, and i to make 72

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1@Dido525 Thank you so much for all your help :) Makes me feel more confident about simplying them!

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{72}=\sqrt{(1)\cdot2\cdot 36}\] \[=6i\sqrt{2}\]

chaguanas
 2 years ago
Best ResponseYou've already chosen the best response.0Getting the i right, but need to look at \[\sqrt{81} and \sqrt{16}\]

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1@chaguanas Would I do \[3i \sqrt{3}\] for 81? and 4i or \[4i \sqrt{4}\] for 16?

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.1do you know what \(\sqrt{81}\)is?

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.1well...\[\sqrt{81}=\sqrt{(1)81}=i9=9i\]

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1@Zarkon Ohh so that's how you do it. You wouldn't factor the 9 out to a 3?

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.1for any \(a>0\) \[\sqrt{a^2}=a\cdot i\] so \[\sqrt{81}=\sqrt{9^2}=9i\]

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{16}=\sqrt{4^2}=4i\]

dellzasaur
 2 years ago
Best ResponseYou've already chosen the best response.1@Zarkon Oh alright! I'm not sure if my teacher taught me about the a>0 thing but that makes sense. Thank you very much :) Explained a lot.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.