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sum1 help with my test asap Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8). (Points : 2) y = -2x - 4 y = -2x - 8 y = -2x + 18 y = -2x – 12

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Helping you on a test is something we cannot do here.
its not relly test but its long like a test i jus thought if i sid test ppl wouldctuallly help me

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Other answers:

@AriPotta heyycan u help plz
@AccessDenied can u help please
put the information into pint-slope form first
that's slope-intercept form
point-slope is y - y1 = m(x - x1)
what do you get after putting the info in?
so y-8=-2(x-2)?
y + 8 = -2(x - 2)
yes, and now "solve for y" to get it into slope-intercept form
my bad -
what did you do wrong?
oh nvm so it would = y=-2x-4 bc u add 8
ok wat about this one Rewrite the equation of a line in point-slope form to slope-intercept form:
1 Attachment
no need to tag me, i'm right here ;)
right now it's in point-slope form. so do the same thing we did to the last one for this one
y-3 wait its a fraction idk wat to do those confudse me
for the last one, we distributed, correct? just do the same thing with this one. 1/2 times x is 1/2x and 1/2 times -8 is..?
no. :/ what's half of 8?
oh 4
oh yea
ok. let's take this by steps starting with what we started with y - 3 = 1/2(x - 8) y - 3 = 1/2x - 4
we need to continue to get into slope-intercept
one step left
+3 n +3 so y=1/2+1
yes, y = 1/2x - 1
ok wat about this one now 2. Write the equation of a line in slope-intercept form passing through (4, 5) and (6, 8)
make a new question thread

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