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tmedina526
When the shuttle bus comes to a sudden stop to avoid hitting a dog, it decelerates uniformly at 5.0 m/s 2 as it slows from 9.5 m/s to 0 m/s. Find the time interval of acceleration for the bus. Answer in units of s
a = Δ v/ Δt -> Δt = Δv/ a = -9.5 /- 5 = ...
given acceleration =-5m/s^2 velocity slow down from v2=9.5 m/s to v1= 0 m/s if the formula for distance is s= change in V/ change in t change in t=change in V/s t= (0-9.5)/-5 t= ?