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Kira_Yamato Group TitleBest ResponseYou've already chosen the best response.0
4(x+y) = x16 4x+4y = x16 3x+4y = 16
 one year ago

Kellie13 Group TitleBest ResponseYou've already chosen the best response.0
the rest of the equation I forgot to place in: 3(xy)=y+10
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
So you have this system of equations\[4(x+y)=x16\]\[3(xy)=y+10\]First solve the first equation for one of the variables\[4x+4y=x16\]\[4y=3x16\]\[y=\frac{3}{4}x4\]Now plug that value into the second equation and solve for the second variable\[3x+3y=y+10\]\[3x+2y=10\]\[3x+2\left(\frac{3}{4}x4\right)=10\]\[3x\frac{3}{2}x8=10\]\[\frac{63}{2}x=18\]\[\frac{9}{2}x=18\]\[x=4\]Now plug that value of x into either equation to solve for y.\[4(x+y)=x16\]\[4(4+y)=416\]\[16+4y=20\]\[4y=4\]\[y=1\]So the solution is x=4, y=1
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
oops, should be 1/
 one year ago

richyw Group TitleBest ResponseYou've already chosen the best response.1
the second last line I dropped the negative it should say \[4y=4\]\[y=1\]So the solution is x=4, y=1
 one year ago

dpgreen Group TitleBest ResponseYou've already chosen the best response.0
just to let you know, you dont only have to do the substitution process, you can also do elimination. 4(x+y)=x−16 −3(x−y)=y+10 distribute to get 4x+4y=x−16 3x+3y=y+10 the subtract the common terms from each other to get final answer
 one year ago
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