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Kira_Yamato
 2 years ago
Best ResponseYou've already chosen the best response.04(x+y) = x16 4x+4y = x16 3x+4y = 16

Kellie13
 2 years ago
Best ResponseYou've already chosen the best response.0the rest of the equation I forgot to place in: 3(xy)=y+10

richyw
 2 years ago
Best ResponseYou've already chosen the best response.1So you have this system of equations\[4(x+y)=x16\]\[3(xy)=y+10\]First solve the first equation for one of the variables\[4x+4y=x16\]\[4y=3x16\]\[y=\frac{3}{4}x4\]Now plug that value into the second equation and solve for the second variable\[3x+3y=y+10\]\[3x+2y=10\]\[3x+2\left(\frac{3}{4}x4\right)=10\]\[3x\frac{3}{2}x8=10\]\[\frac{63}{2}x=18\]\[\frac{9}{2}x=18\]\[x=4\]Now plug that value of x into either equation to solve for y.\[4(x+y)=x16\]\[4(4+y)=416\]\[16+4y=20\]\[4y=4\]\[y=1\]So the solution is x=4, y=1

richyw
 2 years ago
Best ResponseYou've already chosen the best response.1the second last line I dropped the negative it should say \[4y=4\]\[y=1\]So the solution is x=4, y=1

dpgreen
 2 years ago
Best ResponseYou've already chosen the best response.0just to let you know, you dont only have to do the substitution process, you can also do elimination. 4(x+y)=x−16 −3(x−y)=y+10 distribute to get 4x+4y=x−16 3x+3y=y+10 the subtract the common terms from each other to get final answer
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