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calculus130

  • 2 years ago

calculate step by step, if existent, via l'Hopital rule: lim-->2 ln(x^2-3)/x^2-4

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  1. myininaya
    • 2 years ago
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    derivative of top/ derivative of bottom

  2. calculus130
    • 2 years ago
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    i have difficulty with finding the derivative of top ln(x^2-3)

  3. nubeer
    • 2 years ago
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    Hint ln(x+1) [1/(x+1) ] . d/dx (x+1)

  4. calculus130
    • 2 years ago
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    well, what will be the answer if i go step by step?

  5. nubeer
    • 2 years ago
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    i dont know.. why dont you solve and put steps here .. if you do something wrong i wil let u know

  6. richyw
    • 2 years ago
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    \[\frac{d}{dx}\left[\ln\left(x^2-3\right)\right]\]You just need to use the chain rule\[\frac{1}{x^2-3}\cdot\frac{d}{dx}\left(x^2-3\right)=\frac{2x}{x^2-3}\]I already showed you how to check wolfram alpha first for step-by step solutions.

  7. calculus130
    • 2 years ago
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    thank you so much... i was confused whether i can use chain or quotient rule in l'hopital or not

  8. richyw
    • 2 years ago
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    You can use whatever you want to figure out the derivatives. All that matters is the derivative exists (and of course you have an appropriate indeterminate form)

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