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calculus130
calculate step by step, if existent, via l'Hopital rule: lim-->2 ln(x^2-3)/x^2-4
derivative of top/ derivative of bottom
i have difficulty with finding the derivative of top ln(x^2-3)
Hint ln(x+1) [1/(x+1) ] . d/dx (x+1)
well, what will be the answer if i go step by step?
i dont know.. why dont you solve and put steps here .. if you do something wrong i wil let u know
\[\frac{d}{dx}\left[\ln\left(x^2-3\right)\right]\]You just need to use the chain rule\[\frac{1}{x^2-3}\cdot\frac{d}{dx}\left(x^2-3\right)=\frac{2x}{x^2-3}\]I already showed you how to check wolfram alpha first for step-by step solutions.
thank you so much... i was confused whether i can use chain or quotient rule in l'hopital or not
You can use whatever you want to figure out the derivatives. All that matters is the derivative exists (and of course you have an appropriate indeterminate form)