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calculus130 Group Title

calculate step by step, if existent, via l'Hopital rule: lim-->2 ln(x^2-3)/x^2-4

  • one year ago
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  1. myininaya Group Title
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    derivative of top/ derivative of bottom

    • one year ago
  2. calculus130 Group Title
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    i have difficulty with finding the derivative of top ln(x^2-3)

    • one year ago
  3. nubeer Group Title
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    Hint ln(x+1) [1/(x+1) ] . d/dx (x+1)

    • one year ago
  4. calculus130 Group Title
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    well, what will be the answer if i go step by step?

    • one year ago
  5. nubeer Group Title
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    i dont know.. why dont you solve and put steps here .. if you do something wrong i wil let u know

    • one year ago
  6. richyw Group Title
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    \[\frac{d}{dx}\left[\ln\left(x^2-3\right)\right]\]You just need to use the chain rule\[\frac{1}{x^2-3}\cdot\frac{d}{dx}\left(x^2-3\right)=\frac{2x}{x^2-3}\]I already showed you how to check wolfram alpha first for step-by step solutions.

    • one year ago
  7. calculus130 Group Title
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    thank you so much... i was confused whether i can use chain or quotient rule in l'hopital or not

    • one year ago
  8. richyw Group Title
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    You can use whatever you want to figure out the derivatives. All that matters is the derivative exists (and of course you have an appropriate indeterminate form)

    • one year ago
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