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calculate step by step, if existent, via l'Hopital rule:
lim>2 ln(x^23)/x^24
 one year ago
 one year ago
calculate step by step, if existent, via l'Hopital rule: lim>2 ln(x^23)/x^24
 one year ago
 one year ago

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myininayaBest ResponseYou've already chosen the best response.0
derivative of top/ derivative of bottom
 one year ago

calculus130Best ResponseYou've already chosen the best response.0
i have difficulty with finding the derivative of top ln(x^23)
 one year ago

nubeerBest ResponseYou've already chosen the best response.0
Hint ln(x+1) [1/(x+1) ] . d/dx (x+1)
 one year ago

calculus130Best ResponseYou've already chosen the best response.0
well, what will be the answer if i go step by step?
 one year ago

nubeerBest ResponseYou've already chosen the best response.0
i dont know.. why dont you solve and put steps here .. if you do something wrong i wil let u know
 one year ago

richywBest ResponseYou've already chosen the best response.0
\[\frac{d}{dx}\left[\ln\left(x^23\right)\right]\]You just need to use the chain rule\[\frac{1}{x^23}\cdot\frac{d}{dx}\left(x^23\right)=\frac{2x}{x^23}\]I already showed you how to check wolfram alpha first for stepby step solutions.
 one year ago

calculus130Best ResponseYou've already chosen the best response.0
thank you so much... i was confused whether i can use chain or quotient rule in l'hopital or not
 one year ago

richywBest ResponseYou've already chosen the best response.0
You can use whatever you want to figure out the derivatives. All that matters is the derivative exists (and of course you have an appropriate indeterminate form)
 one year ago
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