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 2 years ago
calculate step by step, if existent, via l'Hopital rule:
lim>2 ln(x^23)/x^24
 2 years ago
calculate step by step, if existent, via l'Hopital rule: lim>2 ln(x^23)/x^24

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myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0derivative of top/ derivative of bottom

calculus130
 2 years ago
Best ResponseYou've already chosen the best response.0i have difficulty with finding the derivative of top ln(x^23)

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.0Hint ln(x+1) [1/(x+1) ] . d/dx (x+1)

calculus130
 2 years ago
Best ResponseYou've already chosen the best response.0well, what will be the answer if i go step by step?

nubeer
 2 years ago
Best ResponseYou've already chosen the best response.0i dont know.. why dont you solve and put steps here .. if you do something wrong i wil let u know

richyw
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}\left[\ln\left(x^23\right)\right]\]You just need to use the chain rule\[\frac{1}{x^23}\cdot\frac{d}{dx}\left(x^23\right)=\frac{2x}{x^23}\]I already showed you how to check wolfram alpha first for stepby step solutions.

calculus130
 2 years ago
Best ResponseYou've already chosen the best response.0thank you so much... i was confused whether i can use chain or quotient rule in l'hopital or not

richyw
 2 years ago
Best ResponseYou've already chosen the best response.0You can use whatever you want to figure out the derivatives. All that matters is the derivative exists (and of course you have an appropriate indeterminate form)
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