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mica Group Title

need help im stuck i need to prove that (1-tan x)(1+tan x) = (1-2sin^2x)(sec^2x)

  • one year ago
  • one year ago

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  1. mica Group Title
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    i forgot to mention that i have to start on the left side x.x

    • one year ago
  2. mica Group Title
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    i original problem is prove: cos2x = 1 - tan^2x ---------- 1+tan^2x

    • one year ago
  3. jiteshmeghwal9 Group Title
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    \[(1-\frac{sinx}{cosx}){(1+\frac{sinx}{cosx})}\]\[(1-\frac{\sin^2x}{\cos^2x})\]\[1-\sin^2x \times \frac{1}{\cos^2x}\]\[(1-\sin^2x)(\sec^2x).\]

    • one year ago
  4. mica Group Title
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    aaaaaaaaaa lol gotcha xD thank you

    • one year ago
  5. jiteshmeghwal9 Group Title
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    yw :)

    • one year ago
  6. myininaya Group Title
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    ?

    • one year ago
  7. myininaya Group Title
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    \[(1+\tan(x))(1-\tan(x))\] \[1-\tan^2(x)\] \[1-\frac{\sin^2(x)}{\cos^2(x)}\] He is right until this point.

    • one year ago
  8. jiteshmeghwal9 Group Title
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    ? ------> ??

    • one year ago
  9. jonny1 Group Title
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    hi

    • one year ago
  10. myininaya Group Title
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    Hint 1: Combine the fractions

    • one year ago
  11. myininaya Group Title
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    Hint 2: Rewrite the numerator in terms of sin by using the Pythagorean identity, \[\cos^2(x)=1-\sin^2(x)\]

    • one year ago
  12. jiteshmeghwal9 Group Title
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    |dw:1352617552352:dw|

    • one year ago
  13. myininaya Group Title
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    Yes but that totally is not the same as (1-sin^2(x))(sec^2(x))

    • one year ago
  14. jiteshmeghwal9 Group Title
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    well, i can be wrong here because i'm only studying in middle school

    • one year ago
  15. myininaya Group Title
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    Recall the distributive property a(b+c)=ab+ac

    • one year ago
  16. myininaya Group Title
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    1 is not being multiplied by sec^2(x) so you can not write (1-sin^2(x))(sec^2(x))

    • one year ago
  17. myininaya Group Title
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    @mica you leave already?

    • one year ago
  18. myininaya Group Title
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    Try not to give the full solution next time either even though you didn't do it this time because did it incorrectly anyways.

    • one year ago
  19. jiteshmeghwal9 Group Title
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    He isn't worrying about his question :)

    • one year ago
  20. jiteshmeghwal9 Group Title
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    Okay mam sorry. Thanx for the advice :)

    • one year ago
  21. myininaya Group Title
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    Scenario 1: He just copied what you had and left because he got what he thought he wanted. Scenario 2: He had chores.

    • one year ago
  22. myininaya Group Title
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    We don't want Scenario 1. We want people to actually learn.

    • one year ago
  23. jiteshmeghwal9 Group Title
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    okay mam :)

    • one year ago
  24. 03225186213 Group Title
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    (cos^x−sin^2x)(sec^2x) cos^x=1-sin^2x plug and get ans.

    • one year ago
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