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need help im stuck i need to prove that (1-tan x)(1+tan x) = (1-2sin^2x)(sec^2x)

Mathematics
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i forgot to mention that i have to start on the left side x.x
i original problem is prove: cos2x = 1 - tan^2x ---------- 1+tan^2x
\[(1-\frac{sinx}{cosx}){(1+\frac{sinx}{cosx})}\]\[(1-\frac{\sin^2x}{\cos^2x})\]\[1-\sin^2x \times \frac{1}{\cos^2x}\]\[(1-\sin^2x)(\sec^2x).\]

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aaaaaaaaaa lol gotcha xD thank you
yw :)
?
\[(1+\tan(x))(1-\tan(x))\] \[1-\tan^2(x)\] \[1-\frac{\sin^2(x)}{\cos^2(x)}\] He is right until this point.
? ------> ??
hi
Hint 1: Combine the fractions
Hint 2: Rewrite the numerator in terms of sin by using the Pythagorean identity, \[\cos^2(x)=1-\sin^2(x)\]
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Yes but that totally is not the same as (1-sin^2(x))(sec^2(x))
well, i can be wrong here because i'm only studying in middle school
Recall the distributive property a(b+c)=ab+ac
1 is not being multiplied by sec^2(x) so you can not write (1-sin^2(x))(sec^2(x))
@mica you leave already?
Try not to give the full solution next time either even though you didn't do it this time because did it incorrectly anyways.
He isn't worrying about his question :)
Okay mam sorry. Thanx for the advice :)
Scenario 1: He just copied what you had and left because he got what he thought he wanted. Scenario 2: He had chores.
We don't want Scenario 1. We want people to actually learn.
okay mam :)
(cos^x−sin^2x)(sec^2x) cos^x=1-sin^2x plug and get ans.

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