mica
need help im stuck
i need to prove that
(1tan x)(1+tan x) = (12sin^2x)(sec^2x)



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mica
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i forgot to mention that i have to start on the left side x.x

mica
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i original problem is prove:
cos2x = 1  tan^2x

1+tan^2x

jiteshmeghwal9
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\[(1\frac{sinx}{cosx}){(1+\frac{sinx}{cosx})}\]\[(1\frac{\sin^2x}{\cos^2x})\]\[1\sin^2x \times \frac{1}{\cos^2x}\]\[(1\sin^2x)(\sec^2x).\]

mica
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aaaaaaaaaa lol gotcha xD thank you

jiteshmeghwal9
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yw :)

myininaya
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?

myininaya
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\[(1+\tan(x))(1\tan(x))\]
\[1\tan^2(x)\]
\[1\frac{\sin^2(x)}{\cos^2(x)}\]
He is right until this point.

jiteshmeghwal9
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? > ??

jonny1
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hi

myininaya
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Hint 1: Combine the fractions

myininaya
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Hint 2: Rewrite the numerator in terms of sin by using the Pythagorean identity, \[\cos^2(x)=1\sin^2(x)\]

jiteshmeghwal9
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dw:1352617552352:dw

myininaya
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Yes but that totally is not the same as (1sin^2(x))(sec^2(x))

jiteshmeghwal9
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well, i can be wrong here because i'm only studying in middle school

myininaya
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Recall the distributive property a(b+c)=ab+ac

myininaya
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1 is not being multiplied by sec^2(x) so you can not write
(1sin^2(x))(sec^2(x))

myininaya
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@mica you leave already?

myininaya
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Try not to give the full solution next time either even though you didn't do it this time because did it incorrectly anyways.

jiteshmeghwal9
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He isn't worrying about his question :)

jiteshmeghwal9
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Okay mam sorry. Thanx for the advice :)

myininaya
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Scenario 1: He just copied what you had and left because he got what he thought he wanted.
Scenario 2: He had chores.

myininaya
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We don't want Scenario 1. We want people to actually learn.

jiteshmeghwal9
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okay mam :)

03225186213
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(cos^x−sin^2x)(sec^2x)
cos^x=1sin^2x
plug and get ans.