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rubyhunter

  • 2 years ago

x2-6x-6=0

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  1. richyw
    • 2 years ago
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    we literally just told you how to solve these problems in the last one. For \(f(x)=ax^2+bx+c=0\) \[x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}\]Is there something you don't understand? If so just ask! We're not here to do other peoples homework for them!

  2. rubyhunter
    • 2 years ago
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    ummm ur being rude the other one was easy this one has me confused, and just givin me a formula where i can miss up isnt helpin me -_-

  3. richyw
    • 2 years ago
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    what answer did you get when you tried plugging into the formula?

  4. damith2013
    • 2 years ago
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    \[\left( x-3 \right)^{2}-3^{2}-6=0\] \[\left( x-3 \right)^{2}-15=0\] \[\left( x-3 \right)^{2}=15\] \[\left( x-3 \right)=\pm \sqrt{15}\] \[x =\pm \sqrt{15}+3\] \[x =\sqrt{15}+3\] or \[x =3-\sqrt{15}\]

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