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rubyhunter
 3 years ago
x26x6=0
rubyhunter
 3 years ago
x26x6=0

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richyw
 3 years ago
Best ResponseYou've already chosen the best response.0we literally just told you how to solve these problems in the last one. For \(f(x)=ax^2+bx+c=0\) \[x = \frac{b\pm\sqrt{b^2  4ac}}{2a}\]Is there something you don't understand? If so just ask! We're not here to do other peoples homework for them!

rubyhunter
 3 years ago
Best ResponseYou've already chosen the best response.0ummm ur being rude the other one was easy this one has me confused, and just givin me a formula where i can miss up isnt helpin me _

richyw
 3 years ago
Best ResponseYou've already chosen the best response.0what answer did you get when you tried plugging into the formula?

damith2013
 3 years ago
Best ResponseYou've already chosen the best response.1\[\left( x3 \right)^{2}3^{2}6=0\] \[\left( x3 \right)^{2}15=0\] \[\left( x3 \right)^{2}=15\] \[\left( x3 \right)=\pm \sqrt{15}\] \[x =\pm \sqrt{15}+3\] \[x =\sqrt{15}+3\] or \[x =3\sqrt{15}\]
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