A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Chlorofluorocarbons (CFC's) are organic compounds that have been implicated in ozone depletion. When the CFC known as Freon 12 (CCl2F2) is exposed to UV radiation (wavelength in the range of 10 nm to 400 nm, a bit shorter than visible light), a chlorine atom breaks off from the rest of the molecule. Prove that this is possible by calculating the maximum wavelength capable of breaking the CCl bond.
Average Bond Energy (KJ/mol):
HH: 435
FF: 155
ClCl: 242
CC: 347
C=C: 610
CC triple bound: 836
anonymous
 3 years ago
Chlorofluorocarbons (CFC's) are organic compounds that have been implicated in ozone depletion. When the CFC known as Freon 12 (CCl2F2) is exposed to UV radiation (wavelength in the range of 10 nm to 400 nm, a bit shorter than visible light), a chlorine atom breaks off from the rest of the molecule. Prove that this is possible by calculating the maximum wavelength capable of breaking the CCl bond. Average Bond Energy (KJ/mol): HH: 435 FF: 155 ClCl: 242 CC: 347 C=C: 610 CC triple bound: 836

This Question is Open

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You have the enthalpies of the CC bond and the ClCl bond, both of which are homonuclear. To find the heteronuclear bond enthalpy, CCl, you have you use the formula Professor Cima showed in the lecture. It is the geometric mean of the two homonuclear enthalpies + 96.3(difference of the two electronegativities)^2 ext, use E = ħc / λ where E = energy per photon ħ = plancks constant = 6.626x10^34 J s c = speed of light = 3.00x10^8 m/s λ = wavelength.. E = ħc / λ rearranging λ = ħc / E for CCl... λ = (6.626x10^34 J s) x (3.00x10^8 m/s) / (5.63x10^19 J) = 3.53x10^7 m = 353x10^9 m = 353 nm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you for your help. I have seen this answer on other sites. What i cant get is the 5.63x10^19 J. I keep getting 325 as E(total). ???
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.