Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
jsbrowning
Group Title
Having trouble with this one:
Using implicit differentiation, find the equation of the tangent line at the given point.
xy=6e^2y3x; (3,2)
 2 years ago
 2 years ago
jsbrowning Group Title
Having trouble with this one: Using implicit differentiation, find the equation of the tangent line at the given point. xy=6e^2y3x; (3,2)
 2 years ago
 2 years ago

This Question is Open

rommo419 Group TitleBest ResponseYou've already chosen the best response.0
I am curious, is the problem 6e^(2y3x) with the minus 3x in the exponent? or is it (6e^2y)3x?
 2 years ago

rommo419 Group TitleBest ResponseYou've already chosen the best response.0
because really all that you have to do is take the derivative of both side to get your slope then after you have that you plug the point and the slope into the equation for a line and that will give you your tangent line
 2 years ago

jsbrowning Group TitleBest ResponseYou've already chosen the best response.0
it's: xy=6e^(2y3x) at P(3,2). I'm just having trouble with the implicit differentiation of e's exponent. That's troubling me a little bit.
 2 years ago

rommo419 Group TitleBest ResponseYou've already chosen the best response.0
the derivative of e^u, using the chain rule is (e^u)u'. so when you take the derivative yo get (e^2y3x)(2dy/dx3) Now you want to solve for dy/dx and that is your derivative. so your equation will look like this dy/dx=(e^2y3x)(2dy/dx3) soved for dy/dx dy/dx=3/(12(e^2y3x)) you might want to double check my algebra on that now plg in you values for x and y at that point and that will give you the slope at that point
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.