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0214
Group Title
help please
If f(x) = 1 over 2x + 2 and g(x) = −3x − 1, find g[f(4)].
 one year ago
 one year ago
0214 Group Title
help please If f(x) = 1 over 2x + 2 and g(x) = −3x − 1, find g[f(4)].
 one year ago
 one year ago

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hba Group TitleBest ResponseYou've already chosen the best response.0
I know you can do this.
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
13/10
 one year ago

0214 Group TitleBest ResponseYou've already chosen the best response.0
thats not an option
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
1.3
 one year ago

0214 Group TitleBest ResponseYou've already chosen the best response.0
the only options i can pick are −19 11 −13 −11
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
its really 13/10
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
is f(x) dw:1352643843818:dw
 one year ago

0214 Group TitleBest ResponseYou've already chosen the best response.0
dw:1352643918512:dw
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
its minus then?
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
how about g(x)
 one year ago

0214 Group TitleBest ResponseYou've already chosen the best response.0
plus i forgot to put the other sign
 one year ago

0214 Group TitleBest ResponseYou've already chosen the best response.0
g(x) = −3x − 1, find g[f(4)].
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
there's something wrong with your question
 one year ago

0214 Group TitleBest ResponseYou've already chosen the best response.0
how about this one. If h(x) = x − 1 and j(x) = −4x, find h[j(5)].
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
21
 one year ago

anonymoustwo44 Group TitleBest ResponseYou've already chosen the best response.1
your welcome
 one year ago
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