0214
If f(x) = x − 4 and g(x) = 1 over 2x − 2, find f[g(−6)].



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bahrom7893
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g(6) = 1/(2*(6)2) = 1/(122) = 1/14

bahrom7893
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f [g(6)] = f [ 1/14] = (1/14)  4

0214
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4 isnt an option.

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9
3
−9
−3

bahrom7893
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Well did I say 4 is the answer?
whatever
1/14  4
is.. wait

bahrom7893
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By the way is it:
dw:1352646754665:dw

0214
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first one

bahrom7893
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oh, then scratch what i did before, and use parenthesis when you post the question

bahrom7893
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f(g(6)) = 1/[2*(6)]  2 = (1/12)  2 = (1/12) + (24/12) = 25/12

bahrom7893
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wait that's just g(6)

bahrom7893
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now:
f(g(6)) = f(25/12) = 25/12  4 = (25  48)/12 = 73/12... i don't see where i'm going wrong.

bahrom7893
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@UnkleRhaukus can u go over this real quick?

UnkleRhaukus
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all of it?

bahrom7893
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lol i guess u can just solve the question, i don't see what i did wrong, because i am not getting any of his options

0214
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i sent them to you

0214
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9
3
−9
−3

bahrom7893
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like i said, im not getting any of the options......

UnkleRhaukus
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\[g(x)=\frac1{2x}−2\]
\[g(−6)=\frac1{2(6)}−2=\frac{1}{12}2=\frac{36}{12}=\color\gray{3}\]

bahrom7893
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unkle.... are you sure you added those right?

UnkleRhaukus
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hmm, no

UnkleRhaukus
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\[g(−6)=\frac1{2(6)}−2=\frac{1}{12}\frac{24}{12}=\frac{25}{12}\]

UnkleRhaukus
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\[f(25/12)=\frac{25}{12}4=\frac{25}{12}\frac{48}{12}=\frac{25+48}{12}\color\grey=\color{white}{\frac{73}{12}}\]

UnkleRhaukus
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im getting what you are getting now bahrom

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how about this one
If f(x) = −2x − 4 and g(x) = x + 4, find (f over g)(−8).

0214
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options are
−3
3
−1
1

UnkleRhaukus
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what do you mean by 'over'

UnkleRhaukus
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do you mean \(f\circ g\)

0214
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f/g

UnkleRhaukus
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f(x) = −2x − 4
g(x) = x + 4
(f / g)(x) = ( −2x − 4 ) / ( x + 4)
(f / g)(−8) = ( −2(8) − 4 ) / ( (8) + 4)

0214
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wats the answer

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??

UnkleRhaukus
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( −2(8) − 4 ) / ( (8) + 4)
=( 16 − 4 ) / ( 4)
=