how to find x in 4^x+4^(1/x)=8

how to find x in 4^x+4^(1/x)=8

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is the 2nd term definitely \(4^{\frac{1}{x}}\) and not \(4^{-x}\)?

yes

have you been asked to use any specific methods?
e.g. solve algebraically or numerically?

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