soccerrocks34555
Suppose a parabola has a vertex (-8,-7) and also passes through the point (-7,-4). write the equation of the parabola in vertex form.
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klimenkov
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\(y+7=3(x+8)^2\)
soccerrocks34555
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The answer is y=3(x+8) -7 .. I just dont know how to get it
Brittni0605
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Vertex form is: \[a(x-h)^{2}+k\]
Brittni0605
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\[(h,k) \] is your vertex
soccerrocks34555
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I know that but when I plug the problem into it I don't get the correct answer. What am I doing wrong. Can you please explain how to do it to me
soccerrocks34555
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So -8 and -7 are vertex
Brittni0605
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-8 = h
-7= k
soccerrocks34555
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a ( -7+8) Squared + 7 is that right
klimenkov
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Subtract -7 from both sides of my equation.
Brittni0605
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No.
Brittni0605
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|dw:1352657063399:dw|
soccerrocks34555
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Okay. So now do we have to plug in the other points that it passes through
Brittni0605
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|dw:1352657115052:dw|
soccerrocks34555
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Then do I add 4 to the 7 ?
Brittni0605
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No, because you want to solve for a. SO add the 7 to the 4
soccerrocks34555
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which is 3
Brittni0605
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Yes.
Brittni0605
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|dw:1352657369387:dw|
soccerrocks34555
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ahhh I get it now! Thank you so much for your help. Changing topics can you help me with another problem?
Brittni0605
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Sure.
soccerrocks34555
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What point in the feasible region minimizes the objective function?
X > 0
y>0
y<4
Y < -x +5
Above are the constraints
Objective Function: C= -9x+y
The answer is (5,0) but I don't understand how to get it.
Brittni0605
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gimme a sec please
soccerrocks34555
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okay no problem!
Brittni0605
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|dw:1352658011264:dw|
soccerrocks34555
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I was thinking you had to plug some stuff in to get the final answer
Brittni0605
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I used my graphing calc. I graphed y=-x+5
Brittni0605
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the x intercept of that is (5,0)
soccerrocks34555
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That's the vertex.. right
soccerrocks34555
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Cause have another example of a problem like that.. & that doesn't work
Graph the system of constraints and find the value of x and y that minimize the objective function.
20. Constraints
x ≥ 0
y ≥ 0
y ≤ 3
y < − 2x + 5
Ï
Ì
Ó
Objective function: C = −8x + 5y
Brittni0605
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(5,0) is the vertex because y=-x+5 is a line
soccerrocks34555
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please ignore those random letters
the answer is (5 / 2,0)
soccerrocks34555
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ohh i see what your saying
Brittni0605
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If you graph, y=-2x+5, your x intercept is (5/2, 0)
soccerrocks34555
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how do you see that..
soccerrocks34555
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I put it in my graphing calculator