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soccerrocks34555 Group Title

Suppose a parabola has a vertex (-8,-7) and also passes through the point (-7,-4). write the equation of the parabola in vertex form.

  • one year ago
  • one year ago

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  1. klimenkov Group Title
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    \(y+7=3(x+8)^2\)

    • one year ago
  2. soccerrocks34555 Group Title
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    The answer is y=3(x+8) -7 .. I just dont know how to get it

    • one year ago
  3. Brittni0605 Group Title
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    Vertex form is: \[a(x-h)^{2}+k\]

    • one year ago
  4. Brittni0605 Group Title
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    \[(h,k) \] is your vertex

    • one year ago
  5. soccerrocks34555 Group Title
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    I know that but when I plug the problem into it I don't get the correct answer. What am I doing wrong. Can you please explain how to do it to me

    • one year ago
  6. soccerrocks34555 Group Title
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    So -8 and -7 are vertex

    • one year ago
  7. Brittni0605 Group Title
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    -8 = h -7= k

    • one year ago
  8. soccerrocks34555 Group Title
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    a ( -7+8) Squared + 7 is that right

    • one year ago
  9. klimenkov Group Title
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    Subtract -7 from both sides of my equation.

    • one year ago
  10. Brittni0605 Group Title
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    No.

    • one year ago
  11. Brittni0605 Group Title
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    |dw:1352657063399:dw|

    • one year ago
  12. soccerrocks34555 Group Title
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    Okay. So now do we have to plug in the other points that it passes through

    • one year ago
  13. Brittni0605 Group Title
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    |dw:1352657115052:dw|

    • one year ago
  14. soccerrocks34555 Group Title
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    Then do I add 4 to the 7 ?

    • one year ago
  15. Brittni0605 Group Title
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    No, because you want to solve for a. SO add the 7 to the 4

    • one year ago
  16. soccerrocks34555 Group Title
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    which is 3

    • one year ago
  17. Brittni0605 Group Title
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    Yes.

    • one year ago
  18. Brittni0605 Group Title
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    |dw:1352657369387:dw|

    • one year ago
  19. soccerrocks34555 Group Title
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    ahhh I get it now! Thank you so much for your help. Changing topics can you help me with another problem?

    • one year ago
  20. Brittni0605 Group Title
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    Sure.

    • one year ago
  21. soccerrocks34555 Group Title
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    What point in the feasible region minimizes the objective function? X > 0 y>0 y<4 Y < -x +5 Above are the constraints Objective Function: C= -9x+y The answer is (5,0) but I don't understand how to get it.

    • one year ago
  22. Brittni0605 Group Title
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    gimme a sec please

    • one year ago
  23. soccerrocks34555 Group Title
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    okay no problem!

    • one year ago
  24. Brittni0605 Group Title
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    |dw:1352658011264:dw|

    • one year ago
  25. soccerrocks34555 Group Title
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    okay.

    • one year ago
  26. soccerrocks34555 Group Title
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    I was thinking you had to plug some stuff in to get the final answer

    • one year ago
  27. Brittni0605 Group Title
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    I used my graphing calc. I graphed y=-x+5

    • one year ago
  28. Brittni0605 Group Title
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    the x intercept of that is (5,0)

    • one year ago
  29. soccerrocks34555 Group Title
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    That's the vertex.. right

    • one year ago
  30. soccerrocks34555 Group Title
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    Cause have another example of a problem like that.. & that doesn't work Graph the system of constraints and find the value of x and y that minimize the objective function. 20. Constraints x ≥ 0 y ≥ 0 y ≤ 3 y < − 2x + 5 Ï Ì Ó Objective function: C = −8x + 5y

    • one year ago
  31. Brittni0605 Group Title
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    (5,0) is the vertex because y=-x+5 is a line

    • one year ago
  32. soccerrocks34555 Group Title
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    please ignore those random letters the answer is (5 / 2,0)

    • one year ago
  33. soccerrocks34555 Group Title
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    ohh i see what your saying

    • one year ago
  34. Brittni0605 Group Title
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    If you graph, y=-2x+5, your x intercept is (5/2, 0)

    • one year ago
  35. soccerrocks34555 Group Title
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    how do you see that..

    • one year ago
  36. soccerrocks34555 Group Title
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    I put it in my graphing calculator

    • one year ago
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