Suppose a parabola has a vertex (-8,-7) and also passes through the point (-7,-4). write the equation of the parabola in vertex form.

- anonymous

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- klimenkov

\(y+7=3(x+8)^2\)

- anonymous

The answer is y=3(x+8) -7 .. I just dont know how to get it

- anonymous

Vertex form is: \[a(x-h)^{2}+k\]

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## More answers

- anonymous

\[(h,k) \] is your vertex

- anonymous

I know that but when I plug the problem into it I don't get the correct answer. What am I doing wrong. Can you please explain how to do it to me

- anonymous

So -8 and -7 are vertex

- anonymous

-8 = h
-7= k

- anonymous

a ( -7+8) Squared + 7 is that right

- klimenkov

Subtract -7 from both sides of my equation.

- anonymous

No.

- anonymous

|dw:1352657063399:dw|

- anonymous

Okay. So now do we have to plug in the other points that it passes through

- anonymous

|dw:1352657115052:dw|

- anonymous

Then do I add 4 to the 7 ?

- anonymous

No, because you want to solve for a. SO add the 7 to the 4

- anonymous

which is 3

- anonymous

Yes.

- anonymous

|dw:1352657369387:dw|

- anonymous

ahhh I get it now! Thank you so much for your help. Changing topics can you help me with another problem?

- anonymous

Sure.

- anonymous

What point in the feasible region minimizes the objective function?
X > 0
y>0
y<4
Y < -x +5
Above are the constraints
Objective Function: C= -9x+y
The answer is (5,0) but I don't understand how to get it.

- anonymous

gimme a sec please

- anonymous

okay no problem!

- anonymous

|dw:1352658011264:dw|

- anonymous

okay.

- anonymous

I was thinking you had to plug some stuff in to get the final answer

- anonymous

I used my graphing calc. I graphed y=-x+5

- anonymous

the x intercept of that is (5,0)

- anonymous

That's the vertex.. right

- anonymous

Cause have another example of a problem like that.. & that doesn't work
Graph the system of constraints and find the value of x and y that minimize the objective function.
20. Constraints
x ≥ 0
y ≥ 0
y ≤ 3
y < − 2x + 5
Ï
Ì
Ó
Objective function: C = −8x + 5y

- anonymous

(5,0) is the vertex because y=-x+5 is a line

- anonymous

please ignore those random letters
the answer is (5 / 2,0)

- anonymous

ohh i see what your saying

- anonymous

If you graph, y=-2x+5, your x intercept is (5/2, 0)

- anonymous

how do you see that..

- anonymous

I put it in my graphing calculator

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