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\(y+7=3(x+8)^2\)

The answer is y=3(x+8) -7 .. I just dont know how to get it

Vertex form is: \[a(x-h)^{2}+k\]

\[(h,k) \] is your vertex

So -8 and -7 are vertex

-8 = h
-7= k

a ( -7+8) Squared + 7 is that right

Subtract -7 from both sides of my equation.

No.

|dw:1352657063399:dw|

Okay. So now do we have to plug in the other points that it passes through

|dw:1352657115052:dw|

Then do I add 4 to the 7 ?

No, because you want to solve for a. SO add the 7 to the 4

which is 3

Yes.

|dw:1352657369387:dw|

Sure.

gimme a sec please

okay no problem!

|dw:1352658011264:dw|

okay.

I was thinking you had to plug some stuff in to get the final answer

I used my graphing calc. I graphed y=-x+5

the x intercept of that is (5,0)

That's the vertex.. right

(5,0) is the vertex because y=-x+5 is a line

please ignore those random letters
the answer is (5 / 2,0)

ohh i see what your saying

If you graph, y=-2x+5, your x intercept is (5/2, 0)

how do you see that..

I put it in my graphing calculator