pottersheep
  • pottersheep
Trig Identities....Half Angles help PLEASEEEEE!!! Can someone explain what the teacher wrote on the board for me please??? Cos2A = cos^2A-sin^2A = 1 - 2sin^2 A (What happened here???????)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
sin^2 + cos^2 =1
anonymous
  • anonymous
1-cos^2==sin^2
anonymous
  • anonymous
sub in ... Cos2A=cos^2A-1+cos^2A

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anonymous
  • anonymous
Cos2A=2cos^2A -1
anonymous
  • anonymous
now do same thing with 1-sin^2= cos^2 and you should get the identity you teacher wrote sooooo 1-sin^2=cos^2 sub into Cos2A = cos^2A-sin^2A Cos2A=1-sin^2A-sin^A ==1-2sin^2A
pottersheep
  • pottersheep
HMmm let me process what you said
pottersheep
  • pottersheep
Thank you! I finally get it!
anonymous
  • anonymous
yw

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