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Trig Identities....Half Angles help PLEASEEEEE!!!
Can someone explain what the teacher wrote on the board for me please???
Cos2A = cos^2Asin^2A
= 1  2sin^2 A (What happened here???????)
 one year ago
 one year ago
Trig Identities....Half Angles help PLEASEEEEE!!! Can someone explain what the teacher wrote on the board for me please??? Cos2A = cos^2Asin^2A = 1  2sin^2 A (What happened here???????)
 one year ago
 one year ago

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Rezz5Best ResponseYou've already chosen the best response.1
sub in ... Cos2A=cos^2A1+cos^2A
 one year ago

Rezz5Best ResponseYou've already chosen the best response.1
now do same thing with 1sin^2= cos^2 and you should get the identity you teacher wrote sooooo 1sin^2=cos^2 sub into Cos2A = cos^2Asin^2A Cos2A=1sin^2Asin^A ==12sin^2A
 one year ago

pottersheepBest ResponseYou've already chosen the best response.0
HMmm let me process what you said
 one year ago

pottersheepBest ResponseYou've already chosen the best response.0
Thank you! I finally get it!
 one year ago
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