A community for students.
Here's the question you clicked on:
 0 viewing
tomiko
 2 years ago
is my working correct? i need to find which number is bigger. i concluded that 2*sqrt38 is bigger of the two since 38^2 = 1444
tomiko
 2 years ago
is my working correct? i need to find which number is bigger. i concluded that 2*sqrt38 is bigger of the two since 38^2 = 1444

This Question is Closed

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1yes  correct again. BTW: you can make use of this fact:\[a^2\gt a^21\]\[\therefore a^2\gt (a+1)(a1)\]In this case a=38 so you know that:\[38^2\gt (38+1)(381)\]

tomiko
 2 years ago
Best ResponseYou've already chosen the best response.2how did you just decide a = 38? @asnaseer

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1in your last step you had:\[38^2?39\times37\]

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1so can conclude ? is ">" without actually evaluating \(38^2\)

tomiko
 2 years ago
Best ResponseYou've already chosen the best response.2but 38^2 is "a" but 39 x 37 is not = (a+1)(a1) so how can you compare that way?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1no, a=38, remember the identity I showed was:\[a^2\gt (a+1)(a1)\]so, if a=38 we get:\[38^2\gt(38+1)(381)\]\[\therefore 38^2\gt39\times37\]

tomiko
 2 years ago
Best ResponseYou've already chosen the best response.2wow!! i see it now. where did you know this. i never came across this before?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1nor did I  I just suddenly "spotted" the pattern  that is one of the beauty of maths, you never know what subtleties you will discover. :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.