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REALLY need someone to help explain the steps of this problem to me.

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Find the derivative y' of the function by the equation \[e^{xy}=2(x+y)\]
I am up to the step: \[e^{xy}(xy'+y)=2+2y'\]
the next step looks like this: \[xe^{xy}y'+ye^{xy}=2+2y'\]

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Other answers:

not sure how to get to the step, i'm a little confused at the x and y constants in front of the e value.
get the y's on the same side, and the ys on another
i had to factor in my e^xy : ) that's what i was missing.
i got it now, thanks for taking your time to help me out!

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