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  • 3 years ago

f(x)= 1+7/x-4/x^2 vertical asymptote: x=0 horizontal asymptote: y=1 a) find where is the function increasing/decreasing? b) find the local max/min values c) find where the function is concave up/down, and the inflection points

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  1. guest1234
    • 3 years ago
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    \[f(x)=1+\frac{ 7 }{ x }-\frac{ 4 }{ x^2 }\]

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