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anonymous
 4 years ago
Evaluate the line integral
zdx+xdy+xydz
where is the path of the helix r(t)=(2cost)i+(2sint)j+(1t)k on 0 less than t less than 2
anonymous
 4 years ago
Evaluate the line integral zdx+xdy+xydz where is the path of the helix r(t)=(2cost)i+(2sint)j+(1t)k on 0 less than t less than 2

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0make variable change to cyulindrical coordinates first with r=2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x=2cost y=2sint z=z so: dx=2sint*dt dy=2cost*dt dz=dz

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got to \[\int\limits_{0}^{2\pi} 2 tsintdt +4\cos^2tdt + 4costsintdt\] but i cant figure put how to integrate

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1t is bound above by 2 or 2pi?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1first term: integrate by parts second term: double angle formula \(\cos^2t=\frac12(1+\cos(2t))\) third term: u=sin(t)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1that makes more sense obviously so did you try it yet?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no the homework is not due till tonight so im studying for my test and will try it after!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got 3 pi but it was incorrect.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\int_0^{2\pi}2t\sin t+4\cos^2t+4\sin t\cos tdt\]\[2t\cos t2\sin t+2t+\sin(2t)+2\sin t_0^{2\pi}\]is that what you got?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no my signs were messed up.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1let me check with wolfram...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats correct! i finished it!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i had too many subtraction signs.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1cool :) yeah, the algebra can be the worst in calc 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahhaa. yeah. thanks so much. :)
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