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Evaluate the line integral
zdx+xdy+xydz
where is the path of the helix r(t)=(2cost)i+(2sint)j+(1t)k on 0 less than t less than 2
 one year ago
 one year ago
Evaluate the line integral zdx+xdy+xydz where is the path of the helix r(t)=(2cost)i+(2sint)j+(1t)k on 0 less than t less than 2
 one year ago
 one year ago

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mykoBest ResponseYou've already chosen the best response.1
make variable change to cyulindrical coordinates first with r=2
 one year ago

mykoBest ResponseYou've already chosen the best response.1
x=2cost y=2sint z=z so: dx=2sint*dt dy=2cost*dt dz=dz
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
i got to \[\int\limits_{0}^{2\pi} 2 tsintdt +4\cos^2tdt + 4costsintdt\] but i cant figure put how to integrate
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
t is bound above by 2 or 2pi?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
first term: integrate by parts second term: double angle formula \(\cos^2t=\frac12(1+\cos(2t))\) third term: u=sin(t)
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
\[0\le t \le 2\pi\]
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
that makes more sense obviously so did you try it yet?
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
no the homework is not due till tonight so im studying for my test and will try it after!
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
i got 3 pi but it was incorrect.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
\[\int_0^{2\pi}2t\sin t+4\cos^2t+4\sin t\cos tdt\]\[2t\cos t2\sin t+2t+\sin(2t)+2\sin t_0^{2\pi}\]is that what you got?
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
no my signs were messed up.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
let me check with wolfram...
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
thats correct! i finished it!
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
i had too many subtraction signs.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
cool :) yeah, the algebra can be the worst in calc 3
 one year ago

meggiesmermaidBest ResponseYou've already chosen the best response.0
hahhaa. yeah. thanks so much. :)
 one year ago
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