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mykoBest ResponseYou've already chosen the best response.0
sin (2x) = 2sin(x)cos(x) so sin(2x) /(x*cos(x) =2sin(x)cos(x)/x*cos(x)=2sinx/x which as x>0 goes to 1
 one year ago

mykoBest ResponseYou've already chosen the best response.0
ups sry, forgot about 2 multuplying: lim 2sinx/x=2*1=2 x>0
 one year ago

mykoBest ResponseYou've already chosen the best response.0
sin (2x) can be written like: sin (2x) = 2sin(x)cos(x) substituting this expretion in the original one: sin(2x) /(x*cos(x) =2sin(x)cos(x)/x*cos(x)=2sinx/x taking limits, and noticing that lim as x>0 of sinx/x=1: lim 2sinx/x=2*1=2 x>0
 one year ago

xilinixBest ResponseYou've already chosen the best response.1
why not? l'Hôpital rule
 one year ago

ccappielloBest ResponseYou've already chosen the best response.0
yes, using l'hospital's rule works
 one year ago

VarunsBest ResponseYou've already chosen the best response.0
Don't break your head ! You know that sin(x)=x as x tends to zero. So sin(2x) = 2x. In the denominator, keep x as it is and cos(x)=1. Hence the answer
 one year ago

xilinixBest ResponseYou've already chosen the best response.1
thanks, but the image is ok?
 one year ago

lopusBest ResponseYou've already chosen the best response.1
claro que es posible es solamente derivar arriba y abajo como lo muestras en la imagen y ya
 one year ago
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