andrew.m.higgs 3 years ago Hi All, Can someone please explain the maths behind OPT.2.2 and OPT.2.3. I dont really understand what the results should even look like let alone how to get them. Maths is not a strong point for me. Thanks.

1. pdpinch

OPT.2.2 is a little tricky because you need to iterate over two loops, one for x and one for y, in order to find the values of x and y where y == x**2 + 1. The bit about domains means that you have loop through values of x from -5 to 5 and values of y from 0 to 10. Here's the solutions I got: [(-3, 10), (-2, 5), (-1, 2), (0, 1), (1, 2), (2, 5), (3, 10)] 2.3 is similar, but they don't give you the equation. The equation for a circle of radius 5 is x**2 + y**2 == 5 My solutions for OPT.2.3: [(-2, -1), (-2, 1), (-1, -2), (-1, 2), (1, -2), (1, 2), (2, -1), (2, 1)] I think there's a recitation video that helped me with this.

2. andrew.m.higgs

Thanks pdinch. How do you know what the ranges are for 2.3? It appears as though you changed y's range to range(-5,6) also? Thanks for posting your answers. I now have the same. :-)