A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
combine the fractions and simplify to a multiple of a power of a basic trigonometric function
sinx/cot^2xsinx/cos^2x?
anonymous
 3 years ago
combine the fractions and simplify to a multiple of a power of a basic trigonometric function sinx/cot^2xsinx/cos^2x?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can i change the sinx/cos^2x into tan^2x?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm no. You can take ONE of the cosines, and change it to tanx*(1/cosx) But I dont know if that's the right way to go c: hmm

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large \frac{ \sin x }{ \cot^2 x }\frac{ \sin x }{ \cos^2 x }=\frac{ \sin x }{ (\frac{ \cos^2 x }{ \sin^2 x }) }\frac{ \sin x }{ \cos^2 x }\] \[\large \frac{ \sin x }{ 1 }*\frac{ \sin^2 x }{ \cos^2 x }\frac{ \sin x }{ \cos^2 x }\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1There are multiple ways to simplify it, since there are so many trig identities, so you might find a different way... but this is what I was thinking :3

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large \frac{ \sin^3 x  \sin x }{ \cos^2 x }\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Confused about any of that so far? :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how did you get sinx/1∗sin^2x/cos^2x

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large \frac{ \left(\frac{ a }{ b }\right) }{ \left(\frac{ c }{ d }\right) }=\frac{ a }{ b }*\frac{ d }{ c }\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Remember how you can do that? when dividing fractions :D flip the bottom one and rewrite it as multiplication.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but the top wasn't a fraction yet it was sinx/ (cos^2x/sin^2x)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh wait you put it over 1 to make it into a fraction huh?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \frac{ \left(\sin x \right) }{ \left(\frac{ \cos^2 x }{ \sin^2 x } \right) }=\frac{ \left(\frac{ \sin x }{ 1 } \right) }{ \left(\frac{ \cos^2 x }{ \sin^2 x } \right) }\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1I gotta go, so lemme post the rest of the steps, and you can at least look at them while I'm gone. I won't be here to answer questions though :c

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large \frac{ \sin^3 x  \sin x }{ \cos^2 x }=\frac{ \sin x(\sin^2 x  1) }{ 1\sin^2 x }\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Factored a sinx from each term in the top. Rewrote cos^2 as 1sin^2 using identity :D

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Now if we factor a 1 ouch of each term in the top brackets, we'll have a nice easy cancellation.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large \frac{ \sin x(1\sin^2 x) }{ 1\sin^2 x }=\sin x\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Hopefully I didn't make a mistake in there :D heh
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.