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it's not a perfect square, so it's irrational

how to prove this?

i know this already. but if you were given this question to work out. how would you do it?

all steps are correct so far :)

yo found:\[a^2=5b^2\]therefore \(a^2\) must be a multiple of ???

multiple of 5

yes...

i get \[25m ^{2} = 5b ^{2}\]

yup - now divide both sides by 5 and see what you can say about \(b^2\)...

\[5m ^{2} = b ^{2}\]

... so \(b^2\) must be a multiple of ???

or 5, just like \[a ^{2}\] was

of**

I hope that makes sense?

makes sense. thanks! goodnight!

yw :)
and goodnight to you too.