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Lukecrayonz
Group Title
@jim_thompson5910 help with trig identities real quick?
 2 years ago
 2 years ago
Lukecrayonz Group Title
@jim_thompson5910 help with trig identities real quick?
 2 years ago
 2 years ago

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Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.0
cot x sec^4 x=cot x + 2 tan x + tan^3 x
 2 years ago

surdawi Group TitleBest ResponseYou've already chosen the best response.0
sec^2=1+tan^2
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.0
Steps?:O
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Do you need help?
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
That should help.
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.0
Uhh what site is that.. :O
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.0
@zordoloom
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
cot x sec^4 x=cot x + 2 tan x + tan^3 x cot x sec^4 x=1/tan x + 2 tan x + tan^3 x cot x sec^4 x=1/tan x + 2 tan^2 x/tan x + tan^3 x cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^3 x cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^3 x/1 cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^4 x/tan x cot x sec^4 x=(1 + 2 tan^2 x + tan^4 x)/tan x cot x sec^4 x=(1 + 2z + z^2)/tan x ... Let z = tan^2 x cot x sec^4 x=((z+1)^2)/tan x cot x sec^4 x=((tan^2 x+1)^2)/tan x cot x sec^4 x=((sec^2)^2)/tan x cot x sec^4 x=(sec^4 x)/tan x cot x sec^4 x=cot x sec^4 x
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.0
;__; you have different answers?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
there are different ways to do this, but they are both valid
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
notice how I'm only manipulating the right side and I'm changing it into the left side
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.0
1/tan x + 2 tan^2 x/tan x + tan^3 x (1 + 2 tan^2 x)/tan x + tan^3 x What allowed you to do that?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
1/tan x and 2 tan^2 x/tan x are fractions with the same denominator (tan x)
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
I combined them to get (1 + 2 tan^2 x)/tan x
 2 years ago

Lukecrayonz Group TitleBest ResponseYou've already chosen the best response.0
Thanks a lot @jim_thompson5910 :D
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you're welcome
 2 years ago
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