A community for students.
Here's the question you clicked on:
 0 viewing
Lukecrayonz
 2 years ago
@jim_thompson5910 help with trig identities real quick?
Lukecrayonz
 2 years ago
@jim_thompson5910 help with trig identities real quick?

This Question is Closed

Lukecrayonz
 2 years ago
Best ResponseYou've already chosen the best response.0cot x sec^4 x=cot x + 2 tan x + tan^3 x

Lukecrayonz
 2 years ago
Best ResponseYou've already chosen the best response.0Uhh what site is that.. :O

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1cot x sec^4 x=cot x + 2 tan x + tan^3 x cot x sec^4 x=1/tan x + 2 tan x + tan^3 x cot x sec^4 x=1/tan x + 2 tan^2 x/tan x + tan^3 x cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^3 x cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^3 x/1 cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^4 x/tan x cot x sec^4 x=(1 + 2 tan^2 x + tan^4 x)/tan x cot x sec^4 x=(1 + 2z + z^2)/tan x ... Let z = tan^2 x cot x sec^4 x=((z+1)^2)/tan x cot x sec^4 x=((tan^2 x+1)^2)/tan x cot x sec^4 x=((sec^2)^2)/tan x cot x sec^4 x=(sec^4 x)/tan x cot x sec^4 x=cot x sec^4 x

Lukecrayonz
 2 years ago
Best ResponseYou've already chosen the best response.0;__; you have different answers?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1there are different ways to do this, but they are both valid

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1notice how I'm only manipulating the right side and I'm changing it into the left side

Lukecrayonz
 2 years ago
Best ResponseYou've already chosen the best response.01/tan x + 2 tan^2 x/tan x + tan^3 x (1 + 2 tan^2 x)/tan x + tan^3 x What allowed you to do that?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.11/tan x and 2 tan^2 x/tan x are fractions with the same denominator (tan x)

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1I combined them to get (1 + 2 tan^2 x)/tan x

Lukecrayonz
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks a lot @jim_thompson5910 :D

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1you're welcome
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.