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SugarRainbow
Group Title
help with secx/sinxsinx/cosx!!!!!!!!!!!!!!!!!!!!!!!!!!!!
 one year ago
 one year ago
SugarRainbow Group Title
help with secx/sinxsinx/cosx!!!!!!!!!!!!!!!!!!!!!!!!!!!!
 one year ago
 one year ago

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Shadowys Group TitleBest ResponseYou've already chosen the best response.1
you wanna simplify it? note that sec x = 1/cos x so it becomes \(\frac{1}{sin x cos x}  \frac{sin x}{cos x} \) if you continue to put both fractions into one , you'll notice something beautiful.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
well i got ((1/cosx)/sinx)sinx/cos x and IDK what what to do after that unless i change cosx to 1/secx then can i cancel out the two secx?
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
The sec x cannot be "cancelled". from above, \[\frac{ 1 }{ \sin x \cos x }\frac{ \sin x }{ \cos x }=\frac{ 1\sin x(\sin x) }{ \sin x \cos x}\] and \(cos^2 x+sin^2 x =1 \) :) I think this will help.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
but if you subtract sin from 1 how did you get 1sinx(sinx)? wouldn't it just be 1sinx?
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
hmm...I didn't subtract sin x.. \[\frac{ 1 }{ a }\frac{ 1 }{ b }=\frac{ ba }{ ab }\] I think this should clear things up.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
but you have two things in the first one cuz it's1/sinxcosx not just 1/sinx
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
yup! :) so I multiplied sin x to \( \frac {sin x}{cos x}\) to have the same denominator.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh okay then you seperated it into 1sinx(sinx) because when you multiply it you get 1sin^2x
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
but now what? cuz i know it has to equal cotx but i don't see how
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
well, since from \(cos^2x+sin^2x=1\) we know that \(cos^2 x=1sin^2 x\) so it simplifies to \(\frac{cos^2}{sin x cos x}\)=cot x
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
but there's a cosx in the denominator so how does that work if cot x =cosx/sinx?
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
well, \( \frac{cos^2 x}{ sinxcosx}\)= \(\frac{cos x cosx}{sin x cos x}\) and we can cancel the cos x from the numerator and denominator.
 one year ago

SugarRainbow Group TitleBest ResponseYou've already chosen the best response.0
oh okay!!!! weLl thanx
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
You're welcome :)
 one year ago
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