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collegegirl89

  • 2 years ago

please help!!!! i need to know the horizontal tangents of sin(25x) and the vertical tangents of cos(25x). I got answers of 0 and pi/25 and 25pi/2 and 75pi/2, but my online hw says that theyre wrong

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  1. richyw
    • 2 years ago
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    \(f(x)=\cos(25x)\) has no vertical tangent lines, are you in cartesian coordinates?

  2. richyw
    • 2 years ago
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    for the first one you can just take the derivative and set it equal to zero. so \[\frac{d}{dx}(\sin25x)=\cos (25x)\cdot\frac{d}{dx}25x=25\cos (25x)\]

  3. collegegirl89
    • 2 years ago
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    yeah the interval is from 0 to 2pi

  4. collegegirl89
    • 2 years ago
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    ahh im confused

  5. collegegirl89
    • 2 years ago
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    i thought that cos(25x), when set equal to 0 yielded pi/50 and 3pi/50

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