Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
KonradZuse
Group Title
4.10 #1. In Exercise 1 let
T[a]
and
T[b]
be the operators whose standard matrices are given. Find the standard matrices
for
T[a]
o
T[b]
and
T[b] o T[a]
 2 years ago
 2 years ago
KonradZuse Group Title
4.10 #1. In Exercise 1 let T[a] and T[b] be the operators whose standard matrices are given. Find the standard matrices for T[a] o T[b] and T[b] o T[a]
 2 years ago
 2 years ago

This Question is Closed

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
A =\[\left[\begin{matrix}1 & 2 & 0 \\ 4 & 1 & 3 \\ 5 & 2 & 4\end{matrix}\right]\] B = \[\left[\begin{matrix}2 & 3 & 3 \\ 5 & 0 & 1 \\ 6 & 1 & 7\end{matrix}\right]\] @satellite73
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
what do you mean by the little circle o
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
it's just what the book says, let me screen shot.
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
what does it mean
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
I believe it says the composite of linear transformations.
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
http://tutorial.math.lamar.edu/Classes/LinAlg/LinearTransformations.aspx This has it at the bottom as well, it's not really explaining how we get to an answer... I see from the previous section 4.9 that we use rotations and such but.....
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
Save me :).
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
It gives me the answer already, but I want to know why that's the answer and how to get it...
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
so \[T_A \circ T_b = T_A ( T_b(x) )\]
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
but there is no x here?
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
nor does it say what kind of transformation we are performing...?
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
try this \[T_A\circ T_B=\text A\text B=\left[\begin{matrix}1 & 2 & 0 \\ 4 & 1 & 3 \\ 5 & 2 & 4\end{matrix}\right]\left[\begin{matrix}2 & 3 & 3 \\ 5 & 0 & 1 \\ 6 & 1 & 7\end{matrix}\right]=\]
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
\[\left[\begin{matrix}8 & 3 & 1 \\ 5 & 15 & 8 \\ 44 & 11 & 45\end{matrix}\right]\]
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
wow... Is that all we needed to do? That's some BS LOL.....
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
looks good
 2 years ago

KonradZuse Group TitleBest ResponseYou've already chosen the best response.1
Why is that all we have to do... Why was that so easily konfusing... :'(. I hate Linear >(
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.