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arsh125Best ResponseYou've already chosen the best response.0
how do i evaluate that integral
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\int_1^6\frac{x^2}{\sqrt{x+3}}\text dx\] \(u=x+3\) \(\frac{\text du}{\text dx}=1\) \(\text du=\text dx\) \[=\int_1^6\frac{(u3)^2}{\sqrt{u}}\text du\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[=\int_1^6\frac{u^26u+9}{\sqrt{u}}\text du\] \[=\int_1^6\frac{u^2}{\sqrt{u}}\text du6\int_1^6\frac{u}{\sqrt{u}}\text du+9\int_1^6\frac{1}{\sqrt{u}}\text du\]
 one year ago
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