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oheneba

  • 3 years ago

Find the max/min values for P(x) = -2x^2 +8x-1

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  1. ludwig457
    • 3 years ago
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    on a graphing calculator it reads that 7 is the local maximum (y=7)

  2. RadEn
    • 3 years ago
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    *The first way, find the x-vertec by use formula x=-b/2a = -8/2(-2) = 2 to find the max value, just plug x=2 to P(x) so, P(2) = -2(2)^2+8(2)-1=7 *The 2nd way, use the formula y=-D/4a (with D=b^2-4ac) y_max = -(8^2-4(-2)(-1))/4(-2) = -(64-8)/-8 = -56/-8 = 7

  3. ash2326
    • 3 years ago
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    @oheneba do you know calculus?

  4. oheneba
    • 3 years ago
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    To an extent

  5. zzr0ck3r
    • 3 years ago
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    you dont even need calculus, just use the vertex formula you learn in algebra. you know it is a parabola that opens down, so you will have a max value. it will be the y component of the vertex

  6. oheneba
    • 3 years ago
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    Thanks

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