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ash2326 Group TitleBest ResponseYou've already chosen the best response.1
@odehye We have to find the solution of this \[2x^37x^215x=0\] Take x common \[x(2x^27x15)=0\] Now we have \[x=0\ \text{or}\ (2x^27x15)=0\] So one root is zero Can you solve this quadratic equation to find the other two roots ? \[2x^27x15=0\]
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.1
Do you get this part @odehye ?
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.1
Can you solve the quadratic to find the other two roots?
 one year ago

odehye Group TitleBest ResponseYou've already chosen the best response.0
using P/Q theorem
 one year ago

rob1525 Group TitleBest ResponseYou've already chosen the best response.0
The easiest way is to us the quadratic formual to solve for zeros.
 one year ago

odehye Group TitleBest ResponseYou've already chosen the best response.0
x=5 and x=3/2
 one year ago

odehye Group TitleBest ResponseYou've already chosen the best response.0
@ash2326 x=x=5 and x=3/2
 one year ago
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