anonymous
  • anonymous
Find the zeros for P(x) = 2x^3 - 7x^2 - 15x
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

ash2326
  • ash2326
@odehye We have to find the solution of this \[2x^3-7x^2-15x=0\] Take x common \[x(2x^2-7x-15)=0\] Now we have \[x=0\ \text{or}\ (2x^2-7x-15)=0\] So one root is zero Can you solve this quadratic equation to find the other two roots ? \[2x^2-7x-15=0\]
ash2326
  • ash2326
Do you get this part @odehye ?
anonymous
  • anonymous
yes, i did

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ash2326
  • ash2326
Can you solve the quadratic to find the other two roots?
anonymous
  • anonymous
i'm lost
anonymous
  • anonymous
using P/Q theorem
rob1525
  • rob1525
The easiest way is to us the quadratic formual to solve for zeros.
anonymous
  • anonymous
x=5 and x=-3/2
anonymous
  • anonymous
@ash2326 x=x=5 and x=-3/2

Looking for something else?

Not the answer you are looking for? Search for more explanations.