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ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1@odehye We have to find the solution of this \[2x^37x^215x=0\] Take x common \[x(2x^27x15)=0\] Now we have \[x=0\ \text{or}\ (2x^27x15)=0\] So one root is zero Can you solve this quadratic equation to find the other two roots ? \[2x^27x15=0\]

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1Do you get this part @odehye ?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1Can you solve the quadratic to find the other two roots?

rob1525
 2 years ago
Best ResponseYou've already chosen the best response.0The easiest way is to us the quadratic formual to solve for zeros.

odehye
 2 years ago
Best ResponseYou've already chosen the best response.0@ash2326 x=x=5 and x=3/2
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