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ash2326 Group TitleBest ResponseYou've already chosen the best response.1
@odehye We have to find the solution of this \[2x^37x^215x=0\] Take x common \[x(2x^27x15)=0\] Now we have \[x=0\ \text{or}\ (2x^27x15)=0\] So one root is zero Can you solve this quadratic equation to find the other two roots ? \[2x^27x15=0\]
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.1
Do you get this part @odehye ?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.1
Can you solve the quadratic to find the other two roots?
 2 years ago

odehye Group TitleBest ResponseYou've already chosen the best response.0
using P/Q theorem
 2 years ago

rob1525 Group TitleBest ResponseYou've already chosen the best response.0
The easiest way is to us the quadratic formual to solve for zeros.
 2 years ago

odehye Group TitleBest ResponseYou've already chosen the best response.0
x=5 and x=3/2
 2 years ago

odehye Group TitleBest ResponseYou've already chosen the best response.0
@ash2326 x=x=5 and x=3/2
 2 years ago
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