## odehye Group Title Find the zeros for P(x) = 2x^3 - 7x^2 - 15x one year ago one year ago

1. ash2326 Group Title

@odehye We have to find the solution of this $2x^3-7x^2-15x=0$ Take x common $x(2x^2-7x-15)=0$ Now we have $x=0\ \text{or}\ (2x^2-7x-15)=0$ So one root is zero Can you solve this quadratic equation to find the other two roots ? $2x^2-7x-15=0$

2. ash2326 Group Title

Do you get this part @odehye ?

3. odehye Group Title

yes, i did

4. ash2326 Group Title

Can you solve the quadratic to find the other two roots?

5. odehye Group Title

i'm lost

6. odehye Group Title

using P/Q theorem

7. rob1525 Group Title

The easiest way is to us the quadratic formual to solve for zeros.

8. odehye Group Title

x=5 and x=-3/2

9. odehye Group Title

@ash2326 x=x=5 and x=-3/2