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Area= 1/2 base x height
tan(60)=h/18
h=18tan(60)
right?

should i be using law of sines

why use law of sines?

wait...by law of sines do you mean \[\frac{a}{\sin A} = \frac b{\sin B} = \frac c{\sin C}\]

yes, i have three angles (60) and three sides)
so the how would i then find the height

use pythagorean theorem...you have equilateral triangle |dw:1352707222314:dw|

15.6?

yes

now use your 1/2 bh

A=(1/2)(18)15.6)

yes

140.4units squared

yes

and that solution from earlier would then give me the height?

hmm wait...something's wrong with it...let me find it first

should it be 9 instead of 18

yes it should be 9