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ludwig457

  • 3 years ago

Find the area of an equilateral triangle with side of length 18. (Round your answer to one decimal place.)

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  1. ludwig457
    • 3 years ago
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    Area= 1/2 base x height tan(60)=h/18 h=18tan(60) right?

  2. ludwig457
    • 3 years ago
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    should i be using law of sines

  3. lgbasallote
    • 3 years ago
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    why use law of sines?

  4. lgbasallote
    • 3 years ago
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    wait...by law of sines do you mean \[\frac{a}{\sin A} = \frac b{\sin B} = \frac c{\sin C}\]

  5. ludwig457
    • 3 years ago
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    yes, i have three angles (60) and three sides) so the how would i then find the height

  6. lgbasallote
    • 3 years ago
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    use pythagorean theorem...you have equilateral triangle |dw:1352707222314:dw|

  7. lgbasallote
    • 3 years ago
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    so the height would cut your triangle into two equal parts..|dw:1352707262694:dw| can you see how to get the height now?

  8. ludwig457
    • 3 years ago
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    15.6?

  9. lgbasallote
    • 3 years ago
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    yes

  10. lgbasallote
    • 3 years ago
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    now use your 1/2 bh

  11. ludwig457
    • 3 years ago
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    A=(1/2)(18)15.6)

  12. lgbasallote
    • 3 years ago
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    yes

  13. lgbasallote
    • 3 years ago
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    by the way.. you can also use your solution a while ago... 18tan (60) you don't need law of sines...just use a calculator for that

  14. ludwig457
    • 3 years ago
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    140.4units squared

  15. lgbasallote
    • 3 years ago
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    yes

  16. ludwig457
    • 3 years ago
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    and that solution from earlier would then give me the height?

  17. lgbasallote
    • 3 years ago
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    hmm wait...something's wrong with it...let me find it first

  18. ludwig457
    • 3 years ago
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    should it be 9 instead of 18

  19. lgbasallote
    • 3 years ago
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    yes it should be 9

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