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ludwig457

Find the area of an equilateral triangle with side of length 18. (Round your answer to one decimal place.)

  • one year ago
  • one year ago

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  1. ludwig457
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    Area= 1/2 base x height tan(60)=h/18 h=18tan(60) right?

    • one year ago
  2. ludwig457
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    should i be using law of sines

    • one year ago
  3. lgbasallote
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    why use law of sines?

    • one year ago
  4. lgbasallote
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    wait...by law of sines do you mean \[\frac{a}{\sin A} = \frac b{\sin B} = \frac c{\sin C}\]

    • one year ago
  5. ludwig457
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    yes, i have three angles (60) and three sides) so the how would i then find the height

    • one year ago
  6. lgbasallote
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    use pythagorean theorem...you have equilateral triangle |dw:1352707222314:dw|

    • one year ago
  7. lgbasallote
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    so the height would cut your triangle into two equal parts..|dw:1352707262694:dw| can you see how to get the height now?

    • one year ago
  8. ludwig457
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    15.6?

    • one year ago
  9. lgbasallote
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    yes

    • one year ago
  10. lgbasallote
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    now use your 1/2 bh

    • one year ago
  11. ludwig457
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    A=(1/2)(18)15.6)

    • one year ago
  12. lgbasallote
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    yes

    • one year ago
  13. lgbasallote
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    by the way.. you can also use your solution a while ago... 18tan (60) you don't need law of sines...just use a calculator for that

    • one year ago
  14. ludwig457
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    140.4units squared

    • one year ago
  15. lgbasallote
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    yes

    • one year ago
  16. ludwig457
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    and that solution from earlier would then give me the height?

    • one year ago
  17. lgbasallote
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    hmm wait...something's wrong with it...let me find it first

    • one year ago
  18. ludwig457
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    should it be 9 instead of 18

    • one year ago
  19. lgbasallote
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    yes it should be 9

    • one year ago
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