koli123able
Triangle Solution:-
Two hikers start from the same point ; one walks 9 km heading east, the other one 10 km heading 55 degrees north-east. How far apart are they at the end of their walks?
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ANSWER = 5.79 km
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koli123able
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how to do it
ludwig457
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what is the rate?
koli123able
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sorry i wrote it wrong
koli123able
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Two hikers start from the same point ; one walks 9 km heading east, the other one 10 km heading 55 degrees north-east. How far apart are they at the end of their walks?
ludwig457
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sec
Aperogalics
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|dw:1352708664845:dw|
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|dw:1352708788099:dw|
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@koli123able as theta is 55 degree 2 sides are given 3rd side can be found:)
ludwig457
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law of sines @Aperogalics ?
Aperogalics
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Yup but it is law of Cosines:)
@ludwig457
ludwig457
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oic thanks i havent been over that yet hehe
koli123able
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i solved it by myself but the answer is coming wrong...it s coming 8.81 km however it is 5.79 km
Aperogalics
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let me solve....wait:)
koli123able
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ok
ludwig457
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good question @koli123able
Aperogalics
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sry but my answer comes 5.79:)
let me show it
koli123able
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ok
koli123able
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how??
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c^2=a^2+b^2-2ab cos c
c^2=10^2+9^2-2*10*9* cos35
c^2=181-180*0.8191
c^2=33.5526
c=5.792:)
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@koli123able
koli123able
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how did 35 degrees come..it was not in the question
koli123able
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is there any formula for calculating c
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@koli123able actually the angle 55 is given North-East ,in direction angle is measured only from North and South directions only:)
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so 90-55=35:)
koli123able
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okay