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bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.1@hartnn @UnkleRhaukus this is what i have: x=2^y but i don't know how i'll solve for y.

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.1ok, i'll work out on paper and give answer

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.1i got y= logx/0,301

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1it can be simplified as y= \(\log_2x\) know how ?

bronzegoddess
 2 years ago
Best ResponseYou've already chosen the best response.1yes wait: logx= ylog2 logx/log2= y y= −log2x because of the formula/rule logax= logx/loga and i know the proof thx!
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