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bronzegoddessBest ResponseYou've already chosen the best response.1
@hartnn @UnkleRhaukus this is what i have: x=2^y but i don't know how i'll solve for y.
 one year ago

bronzegoddessBest ResponseYou've already chosen the best response.1
ok, i'll work out on paper and give answer
 one year ago

bronzegoddessBest ResponseYou've already chosen the best response.1
i got y= logx/0,301
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
it can be simplified as y= \(\log_2x\) know how ?
 one year ago

bronzegoddessBest ResponseYou've already chosen the best response.1
yes wait: logx= ylog2 logx/log2= y y= −log2x because of the formula/rule logax= logx/loga and i know the proof thx!
 one year ago
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