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 2 years ago
Find the slope‐intercept equation of the line with the following properties:
Perpendicular to the line x 4y = 2; containing the point (5,2).
 2 years ago
Find the slope‐intercept equation of the line with the following properties: Perpendicular to the line x 4y = 2; containing the point (5,2).

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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0you have any ideas how to start ?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.0@danni2528 Do you know how to find slope of a line from its equation?

jazy
 2 years ago
Best ResponseYou've already chosen the best response.1SlopeIntercept form is: y = mx + b m is slope b is yintercept  Change into SlopeIntercept form. x  4y = 2 Subtract x from both sides. 4y = x + 2 Divide both sides by 4. y = 1/4x  0.5 So you know the slope of this line is 1/4. *****The slope of Perpendicular lines is the opposite reciprocal. So the new line will have a slope of 4/1 or 4.  So far, we have the slope of the new line (4) and we have a given point (5, 2). Use PointSlope formula. \[y  y1 = m(x  x1) \]\[y  2 = 4(x  5) \]Change into SlopeIntercept form. \[y  2 = 4(x  5) \]Distribute.\[y  2 = 4x + 20\]Add 2 to both sides.\[y = 4x + 22\]^There is your equation for a line perpendicular to x 4y = 2.
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