A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
Find the slope‐intercept equation of the line with the following properties:
Perpendicular to the line x 4y = 2; containing the point (5,2).
 2 years ago
Find the slope‐intercept equation of the line with the following properties: Perpendicular to the line x 4y = 2; containing the point (5,2).

This Question is Closed

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0you have any ideas how to start ?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.0@danni2528 Do you know how to find slope of a line from its equation?

jazy
 2 years ago
Best ResponseYou've already chosen the best response.1SlopeIntercept form is: y = mx + b m is slope b is yintercept  Change into SlopeIntercept form. x  4y = 2 Subtract x from both sides. 4y = x + 2 Divide both sides by 4. y = 1/4x  0.5 So you know the slope of this line is 1/4. *****The slope of Perpendicular lines is the opposite reciprocal. So the new line will have a slope of 4/1 or 4.  So far, we have the slope of the new line (4) and we have a given point (5, 2). Use PointSlope formula. \[y  y1 = m(x  x1) \]\[y  2 = 4(x  5) \]Change into SlopeIntercept form. \[y  2 = 4(x  5) \]Distribute.\[y  2 = 4x + 20\]Add 2 to both sides.\[y = 4x + 22\]^There is your equation for a line perpendicular to x 4y = 2.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.