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nivas1811
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in how many ways can 5 prizes be given away to 3 boys when each boy is eligible for one or more prizes..?
 one year ago
 one year ago
nivas1811 Group Title
in how many ways can 5 prizes be given away to 3 boys when each boy is eligible for one or more prizes..?
 one year ago
 one year ago

This Question is Open

nicolebears Group TitleBest ResponseYou've already chosen the best response.0
dw:1352712893295:dw
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
Any one prize can be given to any one of the 3 boys and hence there are 3 ways of distributing each prize. Hence, the 4 prizes can be distributed in 3^4= 81 ways.
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
ok @nivas1811
 one year ago

Aperogalics Group TitleBest ResponseYou've already chosen the best response.0
@mayankdevnani there are 3 boys so first boy can have 1,2 or 3 prizes now for 3,1,1 we have 3ways(3,1,1),(1,3,1),(1,1,3) now for 2,2,1 we have 3 ways(2,1,2),(2,2,1),(1,2,2) so only 6 ways to distribute:)
 one year ago

Aperogalics Group TitleBest ResponseYou've already chosen the best response.0
@nivas1811
 one year ago

nivas1811 Group TitleBest ResponseYou've already chosen the best response.0
@mayankdevnani,@Aperogalics : there are five prizes so there are 3^5 ways to distribute the prizes...
 one year ago

Aperogalics Group TitleBest ResponseYou've already chosen the best response.0
@nivas1811 sry in 3^5 a case comes where 5 prizes are given to one person but you wrote that each boy is eligible for one or more prizes.. so no prize case is eliminated :)
 one year ago

Aperogalics Group TitleBest ResponseYou've already chosen the best response.0
and if one prize is given away then how same can be given to other:)
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
let 1st guy get x prizes, 2nd one y and third one z we are given x+y+z = 5 where x>=1 y>=1 z>=1 we can write the eqn as (x1) + (y1) + (z1) = 2 where now each term inside bracket >=0 it has a direct formulla now for integral solutions of the eqn,,who's background isnt much complex and i can tell you if you desire.. ans would be 4C2 or 6
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
formulla is for x1 + x2 + x3 .... xr = n integral solutions is (n+r1 , r1) given that each x1,x2... is >=0
 one year ago
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