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geerky42 Group Title

\[y = \dfrac{10}{1+x^2}\] \[\text{Find }y'\]

  • one year ago
  • one year ago

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  1. hartnn Group Title
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    know chain rule ?

    • one year ago
  2. geerky42 Group Title
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    Yeah, but how can I apply it?

    • one year ago
  3. hartnn Group Title
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    the question is 10/(1+x^2) right ?

    • one year ago
  4. geerky42 Group Title
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    Wait, let f(x) = 10/x , g(x) = 1+x² so y' = f'(g(x))g'(x) Right?

    • one year ago
  5. geerky42 Group Title
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    Why are there so many viewers? lol.

    • one year ago
  6. hartnn Group Title
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    y= 10/(1+x^2) ? if yes, f(x) = 1/x g(x) = 1+x^2

    • one year ago
  7. hartnn Group Title
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    10 is constant, can be taken out...

    • one year ago
  8. geerky42 Group Title
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    Ok, thanks.

    • one year ago
  9. hartnn Group Title
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    welcome ^_^

    • one year ago
  10. ayman171819 Group Title
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    y=10/(x^2 + 1)

    • one year ago
  11. ayman171819 Group Title
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    y=10/(x^2 + 1)

    • one year ago
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