geerky42
\[y = \dfrac{10}{1+x^2}\]
\[\text{Find }y'\]



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hartnn
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know chain rule ?

geerky42
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Yeah, but how can I apply it?

hartnn
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the question is 10/(1+x^2)
right ?

geerky42
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Wait, let f(x) = 10/x , g(x) = 1+x²
so y' = f'(g(x))g'(x)
Right?

geerky42
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Why are there so many viewers? lol.

hartnn
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y= 10/(1+x^2) ?
if yes,
f(x) = 1/x
g(x) = 1+x^2

hartnn
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10 is constant, can be taken out...

geerky42
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Ok, thanks.

hartnn
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welcome ^_^

ayman171819
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y=10/(x^2 + 1)

ayman171819
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y=10/(x^2 + 1)