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geerky42
 2 years ago
\[y = \dfrac{10}{1+x^2}\]
\[\text{Find }y'\]
geerky42
 2 years ago
\[y = \dfrac{10}{1+x^2}\] \[\text{Find }y'\]

This Question is Closed

geerky42
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah, but how can I apply it?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2the question is 10/(1+x^2) right ?

geerky42
 2 years ago
Best ResponseYou've already chosen the best response.0Wait, let f(x) = 10/x , g(x) = 1+x² so y' = f'(g(x))g'(x) Right?

geerky42
 2 years ago
Best ResponseYou've already chosen the best response.0Why are there so many viewers? lol.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2y= 10/(1+x^2) ? if yes, f(x) = 1/x g(x) = 1+x^2

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.210 is constant, can be taken out...
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