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geerky42

  • 3 years ago

\[y = \dfrac{10}{1+x^2}\] \[\text{Find }y'\]

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  1. hartnn
    • 3 years ago
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    know chain rule ?

  2. geerky42
    • 3 years ago
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    Yeah, but how can I apply it?

  3. hartnn
    • 3 years ago
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    the question is 10/(1+x^2) right ?

  4. geerky42
    • 3 years ago
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    Wait, let f(x) = 10/x , g(x) = 1+x² so y' = f'(g(x))g'(x) Right?

  5. geerky42
    • 3 years ago
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    Why are there so many viewers? lol.

  6. hartnn
    • 3 years ago
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    y= 10/(1+x^2) ? if yes, f(x) = 1/x g(x) = 1+x^2

  7. hartnn
    • 3 years ago
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    10 is constant, can be taken out...

  8. geerky42
    • 3 years ago
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    Ok, thanks.

  9. hartnn
    • 3 years ago
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    welcome ^_^

  10. ayman171819
    • 3 years ago
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    y=10/(x^2 + 1)

  11. ayman171819
    • 3 years ago
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    y=10/(x^2 + 1)

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