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Qaisersatti
 2 years ago
Best ResponseYou've already chosen the best response.0so help us too...brother

prit1010
 2 years ago
Best ResponseYou've already chosen the best response.0dear i've only started but not solved yet!!!

prit1010
 2 years ago
Best ResponseYou've already chosen the best response.0I'll tell help as soon as possible....

chiragsala
 2 years ago
Best ResponseYou've already chosen the best response.2Lab is easy dude. just need an hour more to complete.

Qaisersatti
 2 years ago
Best ResponseYou've already chosen the best response.0i know u r a smart guy @ chiragsala :)....

Qaisersatti
 2 years ago
Best ResponseYou've already chosen the best response.0In the space provided below write an algebraic expression in terms of the device parameters for the bandwidth Δω of the impedance Z looking into this tank circuit. _________ The antenna tank of a Graymark 536 Radio Kit has an inductance L≈0.65mH. The resistance of the inductor RL≈4.0Ω. The equivalent resistance across the capacitor is RC≈490.0kΩ. The capacitor is variable, for tuning. If we tune to a station at f=980.0kHz what is the capacitance, in picoFarads, of the tuning capacitor? __________ What is the bandwidth, in kHz, of the tank at f=980.0kHz? _________ If next we tune to a station at f=1600.0kHz what is the capacitance, in picoFarads, of the tuning capacitor? _________ What is the bandwidth, in kHz, of the tank at f=1600.0kHz? ______________ So it is apparent that this is not the only circuit in the radio that selects the desired station from stations on adjacent channels.

Nurali
 2 years ago
Best ResponseYou've already chosen the best response.0Please Help Based off of the value of Q you determined earlier, you could also estimate the value of the element removed from the circuit! Enter the capacitance in nF or the inductance in mH, depending on which element you determined was removed from the circuit.

prit1010
 2 years ago
Best ResponseYou've already chosen the best response.0@Nurali pls repeat your question.. I can't understand.

Jose.oliveira2
 2 years ago
Best ResponseYou've already chosen the best response.0H11P1 a) 1/(RC*C) + RL/L b) (thats the formula = 1/(2*pi*f)^(2)*L) c) (thats the formula = 1/(RC*C) + RL/L) d) (thats the formula = 1/(2*pi*f)^(2)*L) e) c) (thats the formula = 1/(RC*C) + RL/L) H11P2 a) (The Formula = vm*0.1) b) Cs / Rp c) Cs / Rp d) 0.1*VM(t) H11P3 a)C b)R c)L d ? e) L f) 1000 g) 1 h ?

chiragsala
 2 years ago
Best ResponseYou've already chosen the best response.2Sorry buddy was late because of Diwali preparation. By the way the answers for LAB 11 are: 1)0.001592 2)1.59E7 3)0.0356 4)10 Still if you liked please give best response.
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