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QaisersattiBest ResponseYou've already chosen the best response.0
so help us too...brother
 one year ago

prit1010Best ResponseYou've already chosen the best response.0
dear i've only started but not solved yet!!!
 one year ago

prit1010Best ResponseYou've already chosen the best response.0
I'll tell help as soon as possible....
 one year ago

chiragsalaBest ResponseYou've already chosen the best response.2
Lab is easy dude. just need an hour more to complete.
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.0
i know u r a smart guy @ chiragsala :)....
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.0
In the space provided below write an algebraic expression in terms of the device parameters for the bandwidth Δω of the impedance Z looking into this tank circuit. _________ The antenna tank of a Graymark 536 Radio Kit has an inductance L≈0.65mH. The resistance of the inductor RL≈4.0Ω. The equivalent resistance across the capacitor is RC≈490.0kΩ. The capacitor is variable, for tuning. If we tune to a station at f=980.0kHz what is the capacitance, in picoFarads, of the tuning capacitor? __________ What is the bandwidth, in kHz, of the tank at f=980.0kHz? _________ If next we tune to a station at f=1600.0kHz what is the capacitance, in picoFarads, of the tuning capacitor? _________ What is the bandwidth, in kHz, of the tank at f=1600.0kHz? ______________ So it is apparent that this is not the only circuit in the radio that selects the desired station from stations on adjacent channels.
 one year ago

NuraliBest ResponseYou've already chosen the best response.0
Please Help Based off of the value of Q you determined earlier, you could also estimate the value of the element removed from the circuit! Enter the capacitance in nF or the inductance in mH, depending on which element you determined was removed from the circuit.
 one year ago

prit1010Best ResponseYou've already chosen the best response.0
@Nurali pls repeat your question.. I can't understand.
 one year ago

Jose.oliveira2Best ResponseYou've already chosen the best response.0
H11P1 a) 1/(RC*C) + RL/L b) (thats the formula = 1/(2*pi*f)^(2)*L) c) (thats the formula = 1/(RC*C) + RL/L) d) (thats the formula = 1/(2*pi*f)^(2)*L) e) c) (thats the formula = 1/(RC*C) + RL/L) H11P2 a) (The Formula = vm*0.1) b) Cs / Rp c) Cs / Rp d) 0.1*VM(t) H11P3 a)C b)R c)L d ? e) L f) 1000 g) 1 h ?
 one year ago

chiragsalaBest ResponseYou've already chosen the best response.2
Sorry buddy was late because of Diwali preparation. By the way the answers for LAB 11 are: 1)0.001592 2)1.59E7 3)0.0356 4)10 Still if you liked please give best response.
 one year ago
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