Here's the question you clicked on:
fairuza
integrate sec^3 dx
split it as sec x *sec^2 x
wait, i'll give you general steps http://openstudy.com/users/hartnn#/updates/50960518e4b0d0275a3ccfba see the tips part, there i have given steps to integrate any power of sec x
ok, write sec x as sqrt(1+tan^2 x) put t= tan x dt = sec^2 x dx so your integral becomes sqrt(1+t^2) dt then u have standard formula for this.
in the end don't forget to replace , t by tan x welcome ^_^
i was considering leaving it in trigs
sec^2 = tan^2 + 1 sec * sec^2 = sec tan^2 + sec but yeah, that doesnt quite make a nice transition does it :)
i cant make it. does the sqrt root 1 + t^2 is the final answer or need to be integrate first
the sqrt is a means to rewrite the integral into a more doable format. It still needs to be integrated tho