Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

hartnn Group TitleBest ResponseYou've already chosen the best response.1
split it as sec x *sec^2 x
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
wait, i'll give you general steps http://openstudy.com/users/hartnn#/updates/50960518e4b0d0275a3ccfba see the tips part, there i have given steps to integrate any power of sec x
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok, write sec x as sqrt(1+tan^2 x) put t= tan x dt = sec^2 x dx so your integral becomes sqrt(1+t^2) dt then u have standard formula for this.
 2 years ago

fairuza Group TitleBest ResponseYou've already chosen the best response.1
ooo...thanx a lot
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
in the end don't forget to replace , t by tan x welcome ^_^
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
i was considering leaving it in trigs
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
sec^2 = tan^2 + 1 sec * sec^2 = sec tan^2 + sec but yeah, that doesnt quite make a nice transition does it :)
 2 years ago

fairuza Group TitleBest ResponseYou've already chosen the best response.1
i cant make it. does the sqrt root 1 + t^2 is the final answer or need to be integrate first
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
the sqrt is a means to rewrite the integral into a more doable format. It still needs to be integrated tho
 2 years ago

fairuza Group TitleBest ResponseYou've already chosen the best response.1
ok...got it
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.