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fairuza

  • 3 years ago

integrate sec^3 dx

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  1. hartnn
    • 3 years ago
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    split it as sec x *sec^2 x

  2. fairuza
    • 3 years ago
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    then

  3. hartnn
    • 3 years ago
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    wait, i'll give you general steps http://openstudy.com/users/hartnn#/updates/50960518e4b0d0275a3ccfba see the tips part, there i have given steps to integrate any power of sec x

  4. hartnn
    • 3 years ago
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    ok, write sec x as sqrt(1+tan^2 x) put t= tan x dt = sec^2 x dx so your integral becomes sqrt(1+t^2) dt then u have standard formula for this.

  5. fairuza
    • 3 years ago
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    ooo...thanx a lot

  6. hartnn
    • 3 years ago
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    in the end don't forget to replace , t by tan x welcome ^_^

  7. amistre64
    • 3 years ago
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    i was considering leaving it in trigs

  8. amistre64
    • 3 years ago
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    sec^2 = tan^2 + 1 sec * sec^2 = sec tan^2 + sec but yeah, that doesnt quite make a nice transition does it :)

  9. fairuza
    • 3 years ago
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    i cant make it. does the sqrt root 1 + t^2 is the final answer or need to be integrate first

  10. amistre64
    • 3 years ago
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    the sqrt is a means to rewrite the integral into a more doable format. It still needs to be integrated tho

  11. fairuza
    • 3 years ago
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    ok...got it

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