anonymous
  • anonymous
GEO HELP PLEASE This is the only question I do not know. Find the values of x, y, and z. The diagram is not to scale. https://www.connexus.com/content/media/451160-12172010-104020-AM-1393023501.png
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@Flich it need login:(
anonymous
  • anonymous
Aw man let me try and find one.
anonymous
  • anonymous
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anonymous
  • anonymous
there.
anonymous
  • anonymous
|dw:1352729458794:dw| OK @Flich first find x sum of all angles of a triangle is 180 so m<1+m<2+x=180 x=180-36-63 =180-99 =81:)
anonymous
  • anonymous
Thanks a ton man and thanks for explaining too now I know how to do stuff like this in the future.
ajprincess
  • ajprincess
Sum of interior angles of a triangle=180 63+36+x=180 using this u can find x. x and z are supplementary angles x+z=180 from this z can be found. 13+z+y=180 from this y can be found.
anonymous
  • anonymous
now angle z sum of all angles on a straight line is 180 so z+m<3=180 z=180-81=99:)
anonymous
  • anonymous
Alrighty :)
anonymous
  • anonymous
Any chance I can ask one more Apegogalics. Not understanding this one either.
anonymous
  • anonymous
Given , explain how to construct a square with sides of length AB. (4 points)
anonymous
  • anonymous
again for y sum of all angles of triangle is 180 so 13+81+y=180 y=180-13-99=68:)
anonymous
  • anonymous
*Given AB has a line over it.
anonymous
  • anonymous
@Flich sry i just don't see ur post:)
anonymous
  • anonymous
Okay here it is.
anonymous
  • anonymous
Given ab (AB HAS A LINE OVER IT) , explain how to construct a square with sides of length AB. (4 points)
anonymous
  • anonymous
Thats all it gives and I do not understand. I am terrible at Geo.
anonymous
  • anonymous
@Flich draw a perpendicular to AB at A and B|dw:1352729896337:dw|
anonymous
  • anonymous
Okay.
anonymous
  • anonymous
Now draw a line perpendicular to L at equidistant point from A as the point B is|dw:1352730000383:dw| :)
anonymous
  • anonymous
Okay thanks a ton :)
anonymous
  • anonymous
ur welcome:)

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