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minnie123

  • 3 years ago

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  1. minnie123
    • 3 years ago
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  2. amistre64
    • 3 years ago
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    use the rational roots thrm

  3. nubeer
    • 3 years ago
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    put each of the option in place of x one by one .. for which ever options your answer comes 0. that should be the answer

  4. amistre64
    • 3 years ago
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    all potential rational roots are of the form: \[\pm\frac{factors~last \#}{factors~first\#}\]

  5. amistre64
    • 3 years ago
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    nubeer ... that method would only be viable if it asked for the actual roots; this is asking for the potential roots

  6. nubeer
    • 3 years ago
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    ohh.. ok my bad.. thanks for pointing.

  7. minnie123
    • 3 years ago
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    can one of yu give me an example by using one of the possible answers from the list or with something to get a clearer understanding please

  8. amistre64
    • 3 years ago
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    sure, can you tell me the factors of 3? and the factors of 4? since those are the first and last numbers in the polynomial

  9. minnie123
    • 3 years ago
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    factors? 3*1; 2*2

  10. minnie123
    • 3 years ago
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    or just 3 ; 2

  11. amistre64
    • 3 years ago
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    your on the right track :) the factors of 3: 1,3 the factors of 4: 1,2,4 this creates a pool of potential options of the form:\[\pm\frac{1,3}{1,2,4}\] we can start writing the individual parts by using a terms from the top and bottom as such \[\frac{1,3}{1,2,4}\to~\frac{1}{1},\frac{3}{1},\frac{1}{2},\frac{3}{2},...\]

  12. amistre64
    • 3 years ago
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    the selection choices are then askling you for all the possible rational numbers (and hence real numbers) that you constructed

  13. minnie123
    • 3 years ago
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    i think i know what to do now i'll do it and come back and tell you what i get as answers...

  14. amistre64
    • 3 years ago
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    good :)

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