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 one year ago
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amistre64Best ResponseYou've already chosen the best response.2
use the rational roots thrm
 one year ago

nubeerBest ResponseYou've already chosen the best response.0
put each of the option in place of x one by one .. for which ever options your answer comes 0. that should be the answer
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
all potential rational roots are of the form: \[\pm\frac{factors~last \#}{factors~first\#}\]
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
nubeer ... that method would only be viable if it asked for the actual roots; this is asking for the potential roots
 one year ago

nubeerBest ResponseYou've already chosen the best response.0
ohh.. ok my bad.. thanks for pointing.
 one year ago

minnie123Best ResponseYou've already chosen the best response.0
can one of yu give me an example by using one of the possible answers from the list or with something to get a clearer understanding please
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
sure, can you tell me the factors of 3? and the factors of 4? since those are the first and last numbers in the polynomial
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
your on the right track :) the factors of 3: 1,3 the factors of 4: 1,2,4 this creates a pool of potential options of the form:\[\pm\frac{1,3}{1,2,4}\] we can start writing the individual parts by using a terms from the top and bottom as such \[\frac{1,3}{1,2,4}\to~\frac{1}{1},\frac{3}{1},\frac{1}{2},\frac{3}{2},...\]
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
the selection choices are then askling you for all the possible rational numbers (and hence real numbers) that you constructed
 one year ago

minnie123Best ResponseYou've already chosen the best response.0
i think i know what to do now i'll do it and come back and tell you what i get as answers...
 one year ago
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