anonymous
  • anonymous
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schrodinger
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anonymous
  • anonymous
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amistre64
  • amistre64
use the rational roots thrm
nubeer
  • nubeer
put each of the option in place of x one by one .. for which ever options your answer comes 0. that should be the answer

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amistre64
  • amistre64
all potential rational roots are of the form: \[\pm\frac{factors~last \#}{factors~first\#}\]
amistre64
  • amistre64
nubeer ... that method would only be viable if it asked for the actual roots; this is asking for the potential roots
nubeer
  • nubeer
ohh.. ok my bad.. thanks for pointing.
anonymous
  • anonymous
can one of yu give me an example by using one of the possible answers from the list or with something to get a clearer understanding please
amistre64
  • amistre64
sure, can you tell me the factors of 3? and the factors of 4? since those are the first and last numbers in the polynomial
anonymous
  • anonymous
factors? 3*1; 2*2
anonymous
  • anonymous
or just 3 ; 2
amistre64
  • amistre64
your on the right track :) the factors of 3: 1,3 the factors of 4: 1,2,4 this creates a pool of potential options of the form:\[\pm\frac{1,3}{1,2,4}\] we can start writing the individual parts by using a terms from the top and bottom as such \[\frac{1,3}{1,2,4}\to~\frac{1}{1},\frac{3}{1},\frac{1}{2},\frac{3}{2},...\]
amistre64
  • amistre64
the selection choices are then askling you for all the possible rational numbers (and hence real numbers) that you constructed
anonymous
  • anonymous
i think i know what to do now i'll do it and come back and tell you what i get as answers...
amistre64
  • amistre64
good :)

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