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anonymous
 3 years ago
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anonymous
 3 years ago
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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2use the rational roots thrm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0put each of the option in place of x one by one .. for which ever options your answer comes 0. that should be the answer

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2all potential rational roots are of the form: \[\pm\frac{factors~last \#}{factors~first\#}\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2nubeer ... that method would only be viable if it asked for the actual roots; this is asking for the potential roots

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh.. ok my bad.. thanks for pointing.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can one of yu give me an example by using one of the possible answers from the list or with something to get a clearer understanding please

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2sure, can you tell me the factors of 3? and the factors of 4? since those are the first and last numbers in the polynomial

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2your on the right track :) the factors of 3: 1,3 the factors of 4: 1,2,4 this creates a pool of potential options of the form:\[\pm\frac{1,3}{1,2,4}\] we can start writing the individual parts by using a terms from the top and bottom as such \[\frac{1,3}{1,2,4}\to~\frac{1}{1},\frac{3}{1},\frac{1}{2},\frac{3}{2},...\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2the selection choices are then askling you for all the possible rational numbers (and hence real numbers) that you constructed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think i know what to do now i'll do it and come back and tell you what i get as answers...
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