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minnie123

  • 3 years ago

***Help Wanted*** ***Medal and Fan Earned*** *** Attachment Below***

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  1. minnie123
    • 3 years ago
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  2. surdawi
    • 3 years ago
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    you want help or the answer?

  3. minnie123
    • 3 years ago
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    how do you find the extraneous root? I need help finding it

  4. minnie123
    • 3 years ago
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    @surdawi

  5. surdawi
    • 3 years ago
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    cross multiply |dw:1352736853722:dw|

  6. minnie123
    • 3 years ago
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    done... is this how i find the extraneous root?

  7. minnie123
    • 3 years ago
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    I have y =5 already

  8. surdawi
    • 3 years ago
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    y = 5 is correct

  9. minnie123
    • 3 years ago
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    i only need help finding the EXTRANEOUS ROOT

  10. Zekarias
    • 3 years ago
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    \[\frac{ 1 }{ y-1 }=\frac{ 2 }{ y+2 }....where...y \neq1 ,-2\]\[2(y-1)=y+2\]\[2y-2=y+2\]\[y=4\]

  11. amistre64
    • 3 years ago
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    EXTRAneous roots are roots that are introduced as a byproduct of running thru the algebra. they are values which can be produced thru the algebraic manipulations but are not accepted as solutions to the problem

  12. Zekarias
    • 3 years ago
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    Thus the answers will be y= 1 and y = -2?

  13. minnie123
    • 3 years ago
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    how do yu identify if i have any in this problem?

  14. amistre64
    • 3 years ago
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    extra roots tend to be the result of needing to square something to produce an outcome. 2y-4 = y+1 only has one solution, when y=5

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