anonymous
  • anonymous
***Help Wanted*** ***Medal and Fan Earned*** *** Attachment Below***
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
you want help or the answer?
anonymous
  • anonymous
how do you find the extraneous root? I need help finding it

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
anonymous
  • anonymous
cross multiply |dw:1352736853722:dw|
anonymous
  • anonymous
done... is this how i find the extraneous root?
anonymous
  • anonymous
I have y =5 already
anonymous
  • anonymous
y = 5 is correct
anonymous
  • anonymous
i only need help finding the EXTRANEOUS ROOT
anonymous
  • anonymous
\[\frac{ 1 }{ y-1 }=\frac{ 2 }{ y+2 }....where...y \neq1 ,-2\]\[2(y-1)=y+2\]\[2y-2=y+2\]\[y=4\]
amistre64
  • amistre64
EXTRAneous roots are roots that are introduced as a byproduct of running thru the algebra. they are values which can be produced thru the algebraic manipulations but are not accepted as solutions to the problem
anonymous
  • anonymous
Thus the answers will be y= 1 and y = -2?
anonymous
  • anonymous
how do yu identify if i have any in this problem?
amistre64
  • amistre64
extra roots tend to be the result of needing to square something to produce an outcome. 2y-4 = y+1 only has one solution, when y=5

Looking for something else?

Not the answer you are looking for? Search for more explanations.