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minnie123 Group Title

***Help Wanted*** ***Medal and Fan Earned*** *** Attachment Below***

  • 2 years ago
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  1. minnie123 Group Title
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    • 2 years ago
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  2. surdawi Group Title
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    you want help or the answer?

    • 2 years ago
  3. minnie123 Group Title
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    how do you find the extraneous root? I need help finding it

    • 2 years ago
  4. minnie123 Group Title
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    @surdawi

    • 2 years ago
  5. surdawi Group Title
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    cross multiply |dw:1352736853722:dw|

    • 2 years ago
  6. minnie123 Group Title
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    done... is this how i find the extraneous root?

    • 2 years ago
  7. minnie123 Group Title
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    I have y =5 already

    • 2 years ago
  8. surdawi Group Title
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    y = 5 is correct

    • 2 years ago
  9. minnie123 Group Title
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    i only need help finding the EXTRANEOUS ROOT

    • 2 years ago
  10. Zekarias Group Title
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    \[\frac{ 1 }{ y-1 }=\frac{ 2 }{ y+2 }....where...y \neq1 ,-2\]\[2(y-1)=y+2\]\[2y-2=y+2\]\[y=4\]

    • 2 years ago
  11. amistre64 Group Title
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    EXTRAneous roots are roots that are introduced as a byproduct of running thru the algebra. they are values which can be produced thru the algebraic manipulations but are not accepted as solutions to the problem

    • 2 years ago
  12. Zekarias Group Title
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    Thus the answers will be y= 1 and y = -2?

    • 2 years ago
  13. minnie123 Group Title
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    how do yu identify if i have any in this problem?

    • 2 years ago
  14. amistre64 Group Title
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    extra roots tend to be the result of needing to square something to produce an outcome. 2y-4 = y+1 only has one solution, when y=5

    • 2 years ago
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