## minnie123 2 years ago ***Help Wanted*** ***Medal and Fan Earned*** *** Attachment Below***

1. minnie123

2. surdawi

you want help or the answer?

3. minnie123

how do you find the extraneous root? I need help finding it

4. minnie123

@surdawi

5. surdawi

cross multiply |dw:1352736853722:dw|

6. minnie123

done... is this how i find the extraneous root?

7. minnie123

8. surdawi

y = 5 is correct

9. minnie123

i only need help finding the EXTRANEOUS ROOT

10. Zekarias

$\frac{ 1 }{ y-1 }=\frac{ 2 }{ y+2 }....where...y \neq1 ,-2$$2(y-1)=y+2$$2y-2=y+2$$y=4$

11. amistre64

EXTRAneous roots are roots that are introduced as a byproduct of running thru the algebra. they are values which can be produced thru the algebraic manipulations but are not accepted as solutions to the problem

12. Zekarias

Thus the answers will be y= 1 and y = -2?

13. minnie123

how do yu identify if i have any in this problem?

14. amistre64

extra roots tend to be the result of needing to square something to produce an outcome. 2y-4 = y+1 only has one solution, when y=5