Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Qaisersatti

  • 2 years ago

homework 11 please help....

  • This Question is Closed
  1. Jose.oliveira2
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    H11P1 a) 1/(RC*C) + RL/L b) (thats the formula = 1/(2*pi*f)^(2)*L) c) (thats the formula = 1/(RC*C) + RL/L) d) (thats the formula = 1/(2*pi*f)^(2)*L) e) c) (thats the formula = 1/(RC*C) + RL/L) H11P2 a) (The Formula = vm*0.1) b) Cs / Rp c) Cs / Rp d) 0.1*VM(t) H11P3 a)C b)R c)L d ? e) L f) 1000 g) 1 h ?

  2. Abhaypratap
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    H11P3 d) 4

  3. Jose.oliveira2
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    tks

  4. Jose.oliveira2
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    h = 16

  5. brunofornari
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Jose.oliveira2 the formula doesn't work, or I'm doing it wrong. My values are: L≈0.65mH, RL≈4.0Ω, RC≈490.0kΩ and the tunning capacitors are: 46.0416895277pF and 17.0912179362pF could you help me plz?

  6. Jone133
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I have the same values as brunofornari, and I can't get the results to check ... Any help? Also f=860kHz, So I guess for H11P1b): 1/(2*pi*f)^(2)*L = 1/(2*pi*860k)^(2)*0.65m= 2.22616175526e-17 = 0.0000261p am I doing it right?

  7. brunofornari
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Jone133 No.. your question is: 1/(((2*pi*860k)^(2))*0.65m) = 5.26902190593e-11 = 52.6902190593pF

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.