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Qaisersatti Group Title

homework 11 please help....

  • 2 years ago
  • 2 years ago

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  1. Jose.oliveira2 Group Title
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    H11P1 a) 1/(RC*C) + RL/L b) (thats the formula = 1/(2*pi*f)^(2)*L) c) (thats the formula = 1/(RC*C) + RL/L) d) (thats the formula = 1/(2*pi*f)^(2)*L) e) c) (thats the formula = 1/(RC*C) + RL/L) H11P2 a) (The Formula = vm*0.1) b) Cs / Rp c) Cs / Rp d) 0.1*VM(t) H11P3 a)C b)R c)L d ? e) L f) 1000 g) 1 h ?

    • 2 years ago
  2. Abhaypratap Group Title
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    H11P3 d) 4

    • 2 years ago
  3. Jose.oliveira2 Group Title
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    tks

    • 2 years ago
  4. Jose.oliveira2 Group Title
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    h = 16

    • 2 years ago
  5. brunofornari Group Title
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    @Jose.oliveira2 the formula doesn't work, or I'm doing it wrong. My values are: L≈0.65mH, RL≈4.0Ω, RC≈490.0kΩ and the tunning capacitors are: 46.0416895277pF and 17.0912179362pF could you help me plz?

    • 2 years ago
  6. Jone133 Group Title
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    I have the same values as brunofornari, and I can't get the results to check ... Any help? Also f=860kHz, So I guess for H11P1b): 1/(2*pi*f)^(2)*L = 1/(2*pi*860k)^(2)*0.65m= 2.22616175526e-17 = 0.0000261p am I doing it right?

    • 2 years ago
  7. brunofornari Group Title
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    @Jone133 No.. your question is: 1/(((2*pi*860k)^(2))*0.65m) = 5.26902190593e-11 = 52.6902190593pF

    • 2 years ago
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