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Jose.oliveira2
 2 years ago
Best ResponseYou've already chosen the best response.1H11P1 a) 1/(RC*C) + RL/L b) (thats the formula = 1/(2*pi*f)^(2)*L) c) (thats the formula = 1/(RC*C) + RL/L) d) (thats the formula = 1/(2*pi*f)^(2)*L) e) c) (thats the formula = 1/(RC*C) + RL/L) H11P2 a) (The Formula = vm*0.1) b) Cs / Rp c) Cs / Rp d) 0.1*VM(t) H11P3 a)C b)R c)L d ? e) L f) 1000 g) 1 h ?

brunofornari
 2 years ago
Best ResponseYou've already chosen the best response.0@Jose.oliveira2 the formula doesn't work, or I'm doing it wrong. My values are: L≈0.65mH, RL≈4.0Ω, RC≈490.0kΩ and the tunning capacitors are: 46.0416895277pF and 17.0912179362pF could you help me plz?

Jone133
 2 years ago
Best ResponseYou've already chosen the best response.0I have the same values as brunofornari, and I can't get the results to check ... Any help? Also f=860kHz, So I guess for H11P1b): 1/(2*pi*f)^(2)*L = 1/(2*pi*860k)^(2)*0.65m= 2.22616175526e17 = 0.0000261p am I doing it right?

brunofornari
 2 years ago
Best ResponseYou've already chosen the best response.0@Jone133 No.. your question is: 1/(((2*pi*860k)^(2))*0.65m) = 5.26902190593e11 = 52.6902190593pF
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