Find the volume of a cone with radius 30 in and slant height 50 in. A. 3769.91 in3 B. 3768 in3 C. 113040 in3 D. 37699.11 in3

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Find the volume of a cone with radius 30 in and slant height 50 in. A. 3769.91 in3 B. 3768 in3 C. 113040 in3 D. 37699.11 in3

Mathematics
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can someone help me out here ? i keep trying to solve it but i'm doing something wrong here . @nubeer
hmm can you tell me the formula for vol of cone?
1/3 n r^2 h ?

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Other answers:

|dw:1352739974313:dw|
volume = 1/3* pi *r^2*h|dw:1352740094367:dw| can you find h?
this is what i got for my answer . 47123.8898038
nop you used 50 in calculations.. as its not the height in this case.. can u see the diagram i drew?
yes but now i'm confused on what to do . can you type the equation for me and i will solve ?
well u first have to find the h.. h is the perpendicular height and its not given.. formula for cone is this. volume = 1/3* pi *r^2*h
maybe you can do your steps here so i can point your mistake.
i did : 1/3 * pi * 30^2 * 50
ok.. half is right .. the place where u had put 50 that is wrong. its not 50
what would i put there then ?
ok.. would you able to see the picture if i draw here for u? because i posted pictures above but no respone about that from you.
so i am not sure if you are able to see pictures or something wrong.
|dw:1352740718104:dw|
ok can you see the picture now i just posted?
okay i see it . but what am i supposed to do ?
30 * 50 ?
do u see the "h" with the dotted line?
yes
ok find the value of "h" by Pythagoras theorem.
so 50^2 + 30 ^2 = c^2 ?
not exactly.. the slanting height is "c" the base is "a" and height is "b"..
|dw:1352741077853:dw|
so c^2=a^2+b^2 c=50, a= 30 , b= h can you find h now?
1.6
nooo.. 50^2 - 30^2 = h^2
1600^2
yes h^2 = 1600.. now take square root to find h.
40
good.. this is your h now.. volume = 1/3* pi *r^2*h h=40, r =30 now plug it in formula.
A is my answer !!
yes its A :)
woops just double checked that ! its D . my bad !
lol.. sorry my bad too.. :P
haha its all good ! it just made sense but then i looked at my answer again and i'm like wait a minute .. lol thank you for helping me !
lol you are most welcome anytime :)

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