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hartnn Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest ,can u plz try this ?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
you need the intersection of the two shapes, have you got that yet?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
set formulas for z equal and find what shape the intersection is
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
a circle with a radius of 4
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
the shape of intersection
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
then what are the bounds on r and theta?
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
0<r<4 and 0<theta<2 pi
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
what do i integrate over though??
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
z upper  z lower
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
which function is on top and which is below for z?
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
r(32r^2)^(1/2)
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
yea i never know when a function is on top or on the bottom can we plug in values to figure this out?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
sure, try x=y=0 and you can find out real quick
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
oh, and I see I let you do it backwards, sorry
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
i got it right but i guessed...whats the math behind it?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
hooray :) at the origin x=y=0, so z=x^2+y^2=0 is on the bottom, and z=32x^2y^2=32 is on top
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
hmm i get it plug in x=y=0 to find out which ones on top which ones on the bottom
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
could you have a look at the second question as well
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
by plugging in x=y=0 and comparing values we are asking which one is on top at that point. Unless they cross each other that goes for the whole shape the second one looks a little harder, let me see...
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
dw:1352743460102:dw
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
a strip of the shaded area isdw:1352743660838:dw
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
yup with u
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
sorry that'sdw:1352743785867:dw
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
how did u get the equation of the strip
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
dw:1352743918863:dw
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
i got the first equation when i apply the topbottom rule
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
right, but I think we want to do this in polar anyways
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
yea we do so the bottom equation is right because we want to subtract one to gt the bottom half of the circle
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
http://math.berkeley.edu/~scanez/courses/math53/spring06/problems/review2_solns.pdf
 one year ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
check this out instead=) incase your curious
 one year ago
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