could i get some help with this?

- anonymous

could i get some help with this?

- Stacey Warren - Expert brainly.com

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- hartnn

@TuringTest ,can u plz try this ?

- TuringTest

you need the intersection of the two shapes, have you got that yet?

- anonymous

nope...

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## More answers

- TuringTest

set formulas for z equal and find what shape the intersection is

- anonymous

a circle with a radius of 4

- anonymous

the shape of intersection

- anonymous

then..?

- TuringTest

then what are the bounds on r and theta?

- anonymous

0

- anonymous

what do i integrate over though??

- TuringTest

z upper - z lower

- TuringTest

which function is on top and which is below for z?

- anonymous

r-(32-r^2)^(1/2)

- TuringTest

yes

- anonymous

yea i never know when a function is on top or on the bottom can we plug in values to figure this out?

- TuringTest

sure, try x=y=0 and you can find out real quick

- TuringTest

oh, and I see I let you do it backwards, sorry

- anonymous

i got it right but i guessed...whats the math behind it?

- TuringTest

hooray :)
at the origin x=y=0, so
z=x^2+y^2=0 is on the bottom, and
z=32-x^2-y^2=32 is on top

- anonymous

hmm i get it plug in x=y=0 to find out which ones on top which ones on the bottom

- anonymous

=)!

- anonymous

could you have a look at the second question as well

- TuringTest

by plugging in x=y=0 and comparing values we are asking which one is on top at that point. Unless they cross each other that goes for the whole shape
the second one looks a little harder, let me see...

- TuringTest

|dw:1352743460102:dw|

- TuringTest

a strip of the shaded area is|dw:1352743660838:dw|

- anonymous

yup with u

- TuringTest

sorry that's|dw:1352743785867:dw|

- anonymous

how did u get the equation of the strip

- TuringTest

|dw:1352743918863:dw|

- anonymous

i got the first equation when i apply
the top-bottom rule

- TuringTest

right, but I think we want to do this in polar anyways

- anonymous

yea we do
so the bottom equation is right because we want to subtract one to gt the bottom half of the circle

- anonymous

http://math.berkeley.edu/~scanez/courses/math53/spring06/problems/review2_solns.pdf

- anonymous

check this out instead=) incase your curious

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