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hartnn Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest ,can u plz try this ?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
you need the intersection of the two shapes, have you got that yet?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
set formulas for z equal and find what shape the intersection is
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
a circle with a radius of 4
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
the shape of intersection
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
then what are the bounds on r and theta?
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
0<r<4 and 0<theta<2 pi
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
what do i integrate over though??
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
z upper  z lower
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
which function is on top and which is below for z?
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
r(32r^2)^(1/2)
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
yea i never know when a function is on top or on the bottom can we plug in values to figure this out?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
sure, try x=y=0 and you can find out real quick
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
oh, and I see I let you do it backwards, sorry
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
i got it right but i guessed...whats the math behind it?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
hooray :) at the origin x=y=0, so z=x^2+y^2=0 is on the bottom, and z=32x^2y^2=32 is on top
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
hmm i get it plug in x=y=0 to find out which ones on top which ones on the bottom
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
could you have a look at the second question as well
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
by plugging in x=y=0 and comparing values we are asking which one is on top at that point. Unless they cross each other that goes for the whole shape the second one looks a little harder, let me see...
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
dw:1352743460102:dw
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
a strip of the shaded area isdw:1352743660838:dw
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
sorry that'sdw:1352743785867:dw
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
how did u get the equation of the strip
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
dw:1352743918863:dw
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
i got the first equation when i apply the topbottom rule
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
right, but I think we want to do this in polar anyways
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
yea we do so the bottom equation is right because we want to subtract one to gt the bottom half of the circle
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
http://math.berkeley.edu/~scanez/courses/math53/spring06/problems/review2_solns.pdf
 2 years ago

SABREEN Group TitleBest ResponseYou've already chosen the best response.0
check this out instead=) incase your curious
 2 years ago
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