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SABREEN

  • 3 years ago

could i get some help with this?

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  1. hartnn
    • 3 years ago
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    @TuringTest ,can u plz try this ?

  2. TuringTest
    • 3 years ago
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    you need the intersection of the two shapes, have you got that yet?

  3. SABREEN
    • 3 years ago
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    nope...

  4. TuringTest
    • 3 years ago
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    set formulas for z equal and find what shape the intersection is

  5. SABREEN
    • 3 years ago
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    a circle with a radius of 4

  6. SABREEN
    • 3 years ago
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    the shape of intersection

  7. SABREEN
    • 3 years ago
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    then..?

  8. TuringTest
    • 3 years ago
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    then what are the bounds on r and theta?

  9. SABREEN
    • 3 years ago
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    0<r<4 and 0<theta<2 pi

  10. SABREEN
    • 3 years ago
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    what do i integrate over though??

  11. TuringTest
    • 3 years ago
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    z upper - z lower

  12. TuringTest
    • 3 years ago
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    which function is on top and which is below for z?

  13. SABREEN
    • 3 years ago
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    r-(32-r^2)^(1/2)

  14. TuringTest
    • 3 years ago
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    yes

  15. SABREEN
    • 3 years ago
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    yea i never know when a function is on top or on the bottom can we plug in values to figure this out?

  16. TuringTest
    • 3 years ago
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    sure, try x=y=0 and you can find out real quick

  17. TuringTest
    • 3 years ago
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    oh, and I see I let you do it backwards, sorry

  18. SABREEN
    • 3 years ago
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    i got it right but i guessed...whats the math behind it?

  19. TuringTest
    • 3 years ago
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    hooray :) at the origin x=y=0, so z=x^2+y^2=0 is on the bottom, and z=32-x^2-y^2=32 is on top

  20. SABREEN
    • 3 years ago
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    hmm i get it plug in x=y=0 to find out which ones on top which ones on the bottom

  21. SABREEN
    • 3 years ago
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    =)!

  22. SABREEN
    • 3 years ago
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    could you have a look at the second question as well

  23. TuringTest
    • 3 years ago
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    by plugging in x=y=0 and comparing values we are asking which one is on top at that point. Unless they cross each other that goes for the whole shape the second one looks a little harder, let me see...

  24. TuringTest
    • 3 years ago
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    |dw:1352743460102:dw|

  25. TuringTest
    • 3 years ago
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    a strip of the shaded area is|dw:1352743660838:dw|

  26. SABREEN
    • 3 years ago
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    yup with u

  27. TuringTest
    • 3 years ago
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    sorry that's|dw:1352743785867:dw|

  28. SABREEN
    • 3 years ago
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    how did u get the equation of the strip

  29. TuringTest
    • 3 years ago
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    |dw:1352743918863:dw|

  30. SABREEN
    • 3 years ago
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    i got the first equation when i apply the top-bottom rule

  31. TuringTest
    • 3 years ago
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    right, but I think we want to do this in polar anyways

  32. SABREEN
    • 3 years ago
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    yea we do so the bottom equation is right because we want to subtract one to gt the bottom half of the circle

  33. SABREEN
    • 3 years ago
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    http://math.berkeley.edu/~scanez/courses/math53/spring06/problems/review2_solns.pdf

  34. SABREEN
    • 3 years ago
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    check this out instead=) incase your curious

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