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SABREEN

could i get some help with this?

  • one year ago
  • one year ago

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  1. hartnn
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    @TuringTest ,can u plz try this ?

    • one year ago
  2. TuringTest
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    you need the intersection of the two shapes, have you got that yet?

    • one year ago
  3. SABREEN
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    nope...

    • one year ago
  4. TuringTest
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    set formulas for z equal and find what shape the intersection is

    • one year ago
  5. SABREEN
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    a circle with a radius of 4

    • one year ago
  6. SABREEN
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    the shape of intersection

    • one year ago
  7. SABREEN
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    then..?

    • one year ago
  8. TuringTest
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    then what are the bounds on r and theta?

    • one year ago
  9. SABREEN
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    0<r<4 and 0<theta<2 pi

    • one year ago
  10. SABREEN
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    what do i integrate over though??

    • one year ago
  11. TuringTest
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    z upper - z lower

    • one year ago
  12. TuringTest
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    which function is on top and which is below for z?

    • one year ago
  13. SABREEN
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    r-(32-r^2)^(1/2)

    • one year ago
  14. TuringTest
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    yes

    • one year ago
  15. SABREEN
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    yea i never know when a function is on top or on the bottom can we plug in values to figure this out?

    • one year ago
  16. TuringTest
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    sure, try x=y=0 and you can find out real quick

    • one year ago
  17. TuringTest
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    oh, and I see I let you do it backwards, sorry

    • one year ago
  18. SABREEN
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    i got it right but i guessed...whats the math behind it?

    • one year ago
  19. TuringTest
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    hooray :) at the origin x=y=0, so z=x^2+y^2=0 is on the bottom, and z=32-x^2-y^2=32 is on top

    • one year ago
  20. SABREEN
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    hmm i get it plug in x=y=0 to find out which ones on top which ones on the bottom

    • one year ago
  21. SABREEN
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    =)!

    • one year ago
  22. SABREEN
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    could you have a look at the second question as well

    • one year ago
  23. TuringTest
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    by plugging in x=y=0 and comparing values we are asking which one is on top at that point. Unless they cross each other that goes for the whole shape the second one looks a little harder, let me see...

    • one year ago
  24. TuringTest
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    |dw:1352743460102:dw|

    • one year ago
  25. TuringTest
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    a strip of the shaded area is|dw:1352743660838:dw|

    • one year ago
  26. SABREEN
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    yup with u

    • one year ago
  27. TuringTest
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    sorry that's|dw:1352743785867:dw|

    • one year ago
  28. SABREEN
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    how did u get the equation of the strip

    • one year ago
  29. TuringTest
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    |dw:1352743918863:dw|

    • one year ago
  30. SABREEN
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    i got the first equation when i apply the top-bottom rule

    • one year ago
  31. TuringTest
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    right, but I think we want to do this in polar anyways

    • one year ago
  32. SABREEN
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    yea we do so the bottom equation is right because we want to subtract one to gt the bottom half of the circle

    • one year ago
  33. SABREEN
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    http://math.berkeley.edu/~scanez/courses/math53/spring06/problems/review2_solns.pdf

    • one year ago
  34. SABREEN
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    check this out instead=) incase your curious

    • one year ago
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