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butterflyprincess
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Anyone good with VECTORS? PIC INCLUDED* Suppose that a box is being towed up an inclined plane as shown in the figure. Find the force w needed to make the component of the force parallel to the inclined plane equal to 2.5 lb. Give answer in component form.
 one year ago
 one year ago
butterflyprincess Group Title
Anyone good with VECTORS? PIC INCLUDED* Suppose that a box is being towed up an inclined plane as shown in the figure. Find the force w needed to make the component of the force parallel to the inclined plane equal to 2.5 lb. Give answer in component form.
 one year ago
 one year ago

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hba Group TitleBest ResponseYou've already chosen the best response.4
I got it. Just take the 33 degrees and split it into 15 and 18. (3315=18). Since you know that the 15 degrees has a 2.5 magnitude you can now compose the 33 degree angle as a 15 degree vector with a magnitude of 2.5 and a 18 degree vector of unknown "W" magnitude. Now you know that the "W" vector has a j value( <i,j> component form) of 2.5. So Cos(18)=2.5/W. Then solve for W, which turns out to be about 2.63 magnitude. Plug that back into the component form and you get <cos(33)*2.63, sin(33)*2.63> which turns out to be <2.20,1.43>.
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Cool thanks but like I am a little confused on how you got to this part.. "<cos(33)*2.63, sin(33)*2.63>"
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
you there?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.4
Cos(18)=2.5/w > Solve for w,You get 2.63.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.4
Now we just have to plug it in component form :)
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
ohhhh ok thanks! :DD
 one year ago
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