3√(x+4)-2=13

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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3√(x+4)-2=13

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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  • hba
Why dont you try to solve it :)
i did i got 3. am i right?
  • hba
Can you show me the working @TiaW

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Other answers:

yeah hold on
  • hba
I am waiting.
\[3\sqrt{(x+4)-2}=13\]
is it this?
i redid it. i got 21
3[rt(x+4)] - 2 = 13 3[rt(x+4)] = 15 rt(x+4) = 5 x+4 = 25 x = 25 - 4 x = 21
am i right?
  • hba
You said -2 was also in the root ?
divide both sides by 3 take square on both sides add 2 to both sides and at last subtract 4 from both sides
  • hba
If not you are right.
@hba no its not
  • hba
Well then you are right :) @TiaW
thnxx
  • hba
If it looks like this :) \[3\sqrt{x+4)}-2=13\]
yep dats how it look
  • hba
Awesome :)

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