InsanelyChaotic
Solve x2 + 6x + 7 = 0.
Options are below!!!



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hartnn
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know quadratic formula ?

hartnn
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Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two roots of x are:
\(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

Yahoo!
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\[\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]

InsanelyChaotic
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How do I apply that to this problem? Like i'm having trouble setting it up

hartnn
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none of the options are correct
b^24ac = 3628 = 8
so there should be sqrt 8 in options or sqrt 2

hartnn
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couldn't u find, a,b,c ?

InsanelyChaotic
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Those are the only options.......

hartnn
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then your question must be incorrect

hartnn
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check it

hartnn
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also see your previous question

hartnn
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for this its,
(6+ sqrt 8)/2 = (3+ sqrt2)

InsanelyChaotic
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Solve x2 + 6x + 7 = 0

hartnn
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for that (3+ sqrt2)

InsanelyChaotic
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Oh my goodnes!!!!1 I'm SO sorry

InsanelyChaotic
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i see what occurred

InsanelyChaotic
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the question is: Solve 3x2 + 4x = 2

hartnn
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right,
3x^2+4x2=0
now apply the formula
can u find,a,b,c first ?

InsanelyChaotic
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3, 2, 4?

hartnn
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dw:1352747869498:dw

InsanelyChaotic
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a = 3
b = 4
c = 2

hartnn
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yes.
now what is b^24ac = ?

InsanelyChaotic
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one moment

InsanelyChaotic
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16  4(3)(2)???

InsanelyChaotic
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four times a c?
or four times a times c?

hartnn
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yes, evaluate that

InsanelyChaotic
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It equals 40

hartnn
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yes,
now put all values in formula
and tell me what u get for x.

InsanelyChaotic
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ok

InsanelyChaotic
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This is how I set it up:
4+sq root 4^24(3)(2)/2(3)

InsanelyChaotic
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= 36

InsanelyChaotic
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@hartnn

hartnn
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x1=[4 + sqrt (40)] / (2*3) = ?
x2=[4  sqrt (40)] / (2*3) = ?

hartnn
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got that ^ ?

InsanelyChaotic
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Yes!! :)

hartnn
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got final answer then ?

InsanelyChaotic
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3.7

InsanelyChaotic
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13.4 for the second

hartnn
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from the options ?
3.7 is not in options
keep sqrt 40 as 2sqrt 10 only

InsanelyChaotic
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option b

hartnn
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absolutely correct!
got it ?

InsanelyChaotic
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YES!!!!!!!!!!!! It makes sense! why couldn't I see that on my own?? Thank you!!!!!!