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InsanelyChaotic Group Title

Solve x2 + 6x + 7 = 0. Options are below!!!

  • one year ago
  • one year ago

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  1. InsanelyChaotic Group Title
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    • one year ago
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  5. hartnn Group Title
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    know quadratic formula ?

    • one year ago
  6. hartnn Group Title
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    Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

    • one year ago
  7. Yahoo! Group Title
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    \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

    • one year ago
  8. InsanelyChaotic Group Title
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    How do I apply that to this problem? Like i'm having trouble setting it up

    • one year ago
  9. hartnn Group Title
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    none of the options are correct b^2-4ac = 36-28 = 8 so there should be sqrt 8 in options or sqrt 2

    • one year ago
  10. hartnn Group Title
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    couldn't u find, a,b,c ?

    • one year ago
  11. InsanelyChaotic Group Title
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    Those are the only options.......

    • one year ago
  12. hartnn Group Title
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    then your question must be incorrect

    • one year ago
  13. hartnn Group Title
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    check it

    • one year ago
  14. hartnn Group Title
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    also see your previous question

    • one year ago
  15. hartnn Group Title
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    for this its, (-6+- sqrt 8)/2 = (-3+- sqrt2)

    • one year ago
  16. InsanelyChaotic Group Title
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    Solve x2 + 6x + 7 = 0

    • one year ago
  17. hartnn Group Title
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    for that (-3+- sqrt2)

    • one year ago
  18. InsanelyChaotic Group Title
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    Oh my goodnes!!!!1 I'm SO sorry

    • one year ago
  19. InsanelyChaotic Group Title
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    i see what occurred

    • one year ago
  20. InsanelyChaotic Group Title
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    the question is: Solve 3x2 + 4x = 2

    • one year ago
  21. hartnn Group Title
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    right, 3x^2+4x-2=0 now apply the formula can u find,a,b,c first ?

    • one year ago
  22. InsanelyChaotic Group Title
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    3, 2, 4?

    • one year ago
  23. hartnn Group Title
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    |dw:1352747869498:dw|

    • one year ago
  24. InsanelyChaotic Group Title
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    a = 3 b = 4 c = -2

    • one year ago
  25. hartnn Group Title
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    yes. now what is b^2-4ac = ?

    • one year ago
  26. InsanelyChaotic Group Title
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    one moment

    • one year ago
  27. InsanelyChaotic Group Title
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    16 - 4(3)(-2)???

    • one year ago
  28. InsanelyChaotic Group Title
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    four times a c? or four times a times c?

    • one year ago
  29. hartnn Group Title
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    yes, evaluate that

    • one year ago
  30. InsanelyChaotic Group Title
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    It equals 40

    • one year ago
  31. hartnn Group Title
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    yes, now put all values in formula and tell me what u get for x.

    • one year ago
  32. InsanelyChaotic Group Title
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    ok

    • one year ago
  33. InsanelyChaotic Group Title
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    This is how I set it up: -4+sq root 4^2-4(3)(-2)/2(3)

    • one year ago
  34. InsanelyChaotic Group Title
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    = 36

    • one year ago
  35. InsanelyChaotic Group Title
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    @hartnn

    • one year ago
  36. hartnn Group Title
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    x1=[-4 + sqrt (40)] / (2*3) = ? x2=[-4 - sqrt (40)] / (2*3) = ?

    • one year ago
  37. hartnn Group Title
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    got that ^ ?

    • one year ago
  38. InsanelyChaotic Group Title
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    Yes!! :)

    • one year ago
  39. hartnn Group Title
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    got final answer then ?

    • one year ago
  40. InsanelyChaotic Group Title
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    3.7

    • one year ago
  41. InsanelyChaotic Group Title
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    -13.4 for the second

    • one year ago
  42. hartnn Group Title
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    from the options ? 3.7 is not in options keep sqrt 40 as 2sqrt 10 only

    • one year ago
  43. InsanelyChaotic Group Title
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    option b

    • one year ago
  44. hartnn Group Title
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    absolutely correct! got it ?

    • one year ago
  45. InsanelyChaotic Group Title
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    YES!!!!!!!!!!!! It makes sense! why couldn't I see that on my own?? Thank you!!!!!!

    • one year ago
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