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robert2

  • 3 years ago

Express in lowest terms. 27a^3-1/9a^2-6a+1 @p

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  1. campbell_st
    • 3 years ago
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    lol... to funny....

  2. robert2
    • 3 years ago
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    @ChmE

  3. robert2
    • 3 years ago
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    @Jonask

  4. robert2
    • 3 years ago
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    @sue101

  5. robert2
    • 3 years ago
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    @brookester6

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    • 3 years ago
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    @Hero

  7. Jonask
    • 3 years ago
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    factorise both nominator and denomnator\[27a^3-1=(3a)^3-1=(3a-1)(9a^2+3a+1)\]

  8. brookester6
    • 3 years ago
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    ummm...what grade r u in??

  9. Jonask
    • 3 years ago
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    lowest terms and simplest term do mean the same right

  10. Jonask
    • 3 years ago
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    \[\frac{ (3a-1)(9a^2+3a+1) }{ (3a-1)(3a-1) }=\frac{ 9^2+3a+1 }{ 3a-1 }\]

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