Finding the derivative of \(\ \large f(x)=2sinx+sin^2x ?\)

Finding the derivative of \(\ \large f(x)=2sinx+sin^2x ?\)

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derivative of the sine is the cosine. For the second term, use the chain rule and get derivative of u^2 where u = sin x. Then multiply by derivative of u.

\(\ \text{Here's what I've done so far: } \) \(\ =sinx\times(2+sinx) \) \(\ =cosx\times(2+sinx)+sinx(cosx) \) \(\ =2cosx+sinxcosx+sinxcosx\) \(\ \text{Now what?} \)

= 2cosx + 2sinxcosx = (2cosx)(1 + sinx)

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